CODEWITHSUNDEEP
iosswiftuitableviewuiapplication
AziCode
AziCode

Reputation: 2692

How to retrieve the detailedText from a cell then use it in a function?

I'm trying to retrieve the detailedText contained in a UITableView Cell (which is a phone number "String") and then Use it in a function that will make a phone call.

I'm sure that I'm doing something wrong with force unwrapping the optional

func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
   let cell = tableView.cellForRowAtIndexPath(indexPath)
   let getPhone = cell?.detailTextLabel?.text

   if indexPath.section == 0 && indexPath.row == 0 {
  
     if let phoneNumber = getPhone{
       openPhoneApp(phoneNumber)
     }
}

// Open Phone App
func openPhoneApp(phoneNum: String){
  UIApplication.sharedApplication().openURL(NSURL(string: "tel:\(phoneNum)")!)
}

enter image description here

Upvotes: 0

Views: 61

Answers (3)

Lu_
Lu_

Reputation: 2685

Please use tel:// scheme and always call 

UIApplication.sharedApplication().canOpenURL

before

Upvotes: 1

NiñoScript
NiñoScript

Reputation: 4593

Don't use force unwrapping if you're not 100% sure it can be unwrapped. And avoid it if possible even then!

Your openPhoneApp function must receive a non-nil string, so everything's ok up to that moment.

Try to replace your force unwrap with something like this:

func openPhoneApp(phoneNum: String) {
    guard let url = NSURL(string: "tel:\(phoneNum)") else {
        print("badly formed telephone url")
        return
    }
    UIApplication.sharedApplication().openURL(url)
}

Although I'd argue that your function's name implies that it WILL open the phone app, so maybe you should just go and ask for a correctly formed URL, like this:

func openPhoneApp(phoneURL: NSURL) {
    UIApplication.sharedApplication().openURL(phoneURL)
}

and check for that kind of stuff before even calling it:

if let phone = getPhone, phoneURL = NSURL(string: "tel:\(phone)") {
    openPhoneApp(phoneURL)
}

Upvotes: 3

Surbhi Garg
Surbhi Garg

Reputation: 414

Did you checked the value of phoneNumber variable? it could be nil.

You can check this answer: I think this will solve your problem.

What does "fatal error: unexpectedly found nil while unwrapping an Optional value" mean?

specifically this answer

https://stackoverflow.com/a/35683816/5660422

Upvotes: 1

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