CODEWITHSUNDEEP
javascriptarrayssortingmultidimensional-array
ellier7
ellier7

Reputation: 427

Sort Multidimensional array in descending order

I have an array that is currently sorted by the first value:

[ [ 'a', 3 ],
  [ 'c', 3 ],
  [ 'd', 1 ],
  [ 'e', 2 ],
  [ 'f', 1 ],
  [ 'g', 1 ],
  [ 'i', 7 ],
  [ 'l', 3 ],
  [ 'o', 2 ],
  [ 'p', 2 ],
  [ 'r', 2 ],
  [ 's', 3 ],
  [ 't', 1 ],
  [ 'u', 2 ],
  [ 'x', 1 ] ]

I would like to sort the digits in descending order to get: 

[ [ 'i', 7 ],
  [ 'a', 3 ],
  [ 'c', 3 ],
  [ 'l', 3 ],
  [ 's', 3 ],
  [ 'e', 2 ],
  [ 'o', 2 ] ......]

Upvotes: 0

Views: 1964

Answers (2)

Usir
Usir

Reputation: 21

Use Array.sort([compareFunction])

function comparator(a, b) {    
  if (a[1] > b[1]) return -1
  if (a[1] < b[1]) return 1
  return 0
}

myArray = myArray.sort(comparator)

edit for comment:

Here is a jslint showing it in action: https://jsfiddle.net/49ed0Lj4/1/

Upvotes: 1

tomision
tomision

Reputation: 994

The sort method in Array

var arr = [
    ['a', 3],
    ['c', 3],
    ['d', 1],
    ['e', 2],
    ['f', 1],
    ['g', 1],
    ['i', 7],
    ['l', 3],
    ['o', 2],
    ['p', 2],
    ['r', 2],
    ['s', 3],
    ['t', 1],
    ['u', 2],
    ['x', 1]
];

arr.sort(function(a, b) {
    return b[1] - a[1]
})

Maybe you need to sort by both the English letters and number. You can change the callback function to do this.

Upvotes: 0

Related Questions