CODEWITHSUNDEEP
bashshell
user3447653
user3447653

Reputation: 4148

Regular expression matching using shell script

I have created a shell script below that checks whether the file out.txt contains any line with the text "Billing_20160210". I am getting the error in the regular expression part which states that "[[: not found". Not sure whether i am missing something. Any help would be appreciated.

#!/bin/bash
bq ls test:Dataset_test > out.txt
cat out.txt | while read LINE
do 
  if [ LINE = *"Billing_20160210"* ]; 
  then 
    echo "Processing $LINE"
  fi
done

Edit not working:

#!/bin/bash
bq ls geotab-bigdata-test:JS_test > out.txt
cat out.txt | while read LINE
do 
 if [[ $LINE == *"DailyBillingTest_20160210"* ]];
 then 
  echo "Processing $LINE"
 fi
done

Upvotes: 0

Views: 83

Answers (1)

hek2mgl
hek2mgl

Reputation: 157992

Don't use a shell loop to filter a file line by line. Use grep as a filter here:

grep 'Billing_20160210' out.txt | while read -r line ; do
    echo "processing ${line}"
done

Or even without a temporary file:

bq ls test:Dataset_test | grep 'Billing_20160210' | while read -r line ; do
    echo "processing ${line}"
done

Upvotes: 1

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