CODEWITHSUNDEEP
php
Pennywise83
Pennywise83

Reputation: 1784

PHP - Increment a value

I'd like to increment a value in a 3-digits format.

For example:

$start_value = 000;
while () {
do something;
$start_value++;
}

In this way I have this result:

$start_value = 000;
$start_value = 1;
$start_value = 2;
$start_value = 3;

and so on

instead of '001', '002', '003'

How I can accomplish this result?

Upvotes: 2

Views: 3471

Answers (3)

Benoit
Benoit

Reputation: 79165

You are making a big mistake here. 000 in code is an octal number. Any literal number starting with a 0 in many programming languages is considered an octal literal. If you want to store 000, you need a string, not a number.

$start_value = "000";
while((int) $start_value /*--apply condition --*/) {
    do something;
    $start_value = str_pad((int) $start_value+1, 3 ,"0",STR_PAD_LEFT);
}

Upvotes: 4

Gurucharan Balakuntla Maheshku
Gurucharan Balakuntla Maheshku

Reputation: 2489

It goes like this. In PHP there is no concept of datatypes everything is determined in runtime based on where and how it is used. 

<?php
 $start_value = 000;
 while ($start_value < 10) {
 //your logic goes here
  $start_value++;
 printf("[%03s]\n",$start_value);
 }
?>

Output : [001] [002] [003] [004] [005] [006] [007] [008] [009] [010]

So you can do all the calculation. Where ever you want to print the value, you can use printf with format specifiers.!! Hope it helps.

Upvotes: 0

Jim
Jim

Reputation: 18853

Using sprintf you can accomplish this with:

echo sprintf("%03d", $start_value++) . "<br>";

Hopefully that is what you were after.

Implementing it with your code:

$start_value = 000;
while () {
    do something;
    $start_value = sprintf("%03d", $start_value++);
}

Upvotes: 11

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