CODEWITHSUNDEEP
c++11goto
Ibrahim Ipek
Ibrahim Ipek

Reputation: 525

Giving labels as a argument in C/C++

We have a label:

LABEL:
    //Do something.

and we have a function. We want pass LABEL as a argument to this function (otherwise we can't access labels in a function), and in some condition we want to jump this label. Is it possible?

I'm giving a example (pseudocode) for clarification: 

GameMenu: //This part will be executed when program runs
//Go in a loop and continue until user press to [ENTER] key

while(Game.running) //Main loop for game
{
    Game.setKey(GameMenu, [ESCAPE]); //If user press to [ESCAPE] jump into GameMenu
    //And some other stuff for game
}

Upvotes: 0

Views: 1561

Answers (3)

flau
flau

Reputation: 1380

It seems like it may be worth refactoring your code to something similar:

void GameMenu() {
    // Show menu
}

void SomethingElse() {
    // Do something else
}

int main(int argc, char **argv) {

    (...)

    while(Game.running) {
        int key = GetKey();
        switch(key) {
        case ESCAPE:
            GameMenu();
            break;
        case OTHER_KEY:
            SomethingElse();
            break;
        }
    }
}

Upvotes: 1

Simple
Simple

Reputation: 14390

This sounds like an XY problem. You might want a state machine:

enum class State {
    menu,
    combat,
};

auto state = State::combat;
while (Game.running) {
    switch (state) {
    case State::combat:
        // Detect that Escape has been pressed (open menu).
        state = State::menu;
        break;

    case State::menu:
        // Detect that Escape has been pressed (close menu).
        state = State::combat;
        break;
    }
}

Upvotes: 5

Sergio
Sergio

Reputation: 8209

You can use setjmp()/longjmp() to jump to some point in outer scope even to outer function. But note - jump target scope must be alive at the moment of jump.

Upvotes: -1

Related Questions