CODEWITHSUNDEEP
swift
Nitesh
Nitesh

Reputation: 2024

Replace array contain according to its occurrences

How to replace number string with its corresponding Alphabet Characters in Array.

Example:
["1","2","3","3","2","3"]

Replace: 1 -> A, 2-> B, 3-> C

Result should be 
["A","B","C","C","B","C"]

Upvotes: 0

Views: 123

Answers (3)

Yury
Yury

Reputation: 6114

You may use Dictionary for replacement rules:

let array = ["1", "2", "3", "3", "2", "3"]

let replacementRules = ["1": "A", "2": "B", "3": "C"]

let result = array.map{replacementRules[$0] ?? $0}
print(result)
//["A", "B", "C", "C", "B", "C"]

Upvotes: 3

Sam Fischer
Sam Fischer

Reputation: 1472

var arr = ["1","2","3","3","2","3"]
for i in 0..<arr.count {
    switch(arr[i]) {
        case "1":
            arr[i] = "A"
            break
        case "2":
            arr[i] = "B"
            break
        case "3":
            arr[i] = "C"
            break
    default: break
    }

}

Upvotes: 1

Nirav D
Nirav D

Reputation: 72420

If your array contain string value till 1-26, you can try like this

    let alphabetArray = ["A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"]
    let arr = ["1","2","3","3","2","3"]
    var newArr = [String]()
    newArr = arr.map { (item) in
        alphabetArray[Int(item)! - 1]
    }
    print(newArr)

Upvotes: 1

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