CODEWITHSUNDEEP
angularjsregex
anju
anju

Reputation: 609

Regular expression validation error

I'm using regex for validating numbers in angularjs. But my code shows validation error when the number exceeds 9 digits.Could someone please help me to rectify my code such that any digits of number can be entered.

What I have tried is :

ng-pattern="/^\d{0,9}?$/"

Upvotes: 4

Views: 181

Answers (4)

Dmitry Egorov
Dmitry Egorov

Reputation: 9650

Just change the {0,9} quantifier with the *. And remove the ? -- it's useless:

ng-pattern="/^\d*$/"

For decimal values:

ng-pattern="/^\d*(\.\d+)?$/"

Upvotes: 2

Bohemian
Bohemian

Reputation: 425033

I suspect the problem is understanding the difference between:

  • {0,9}
  • [0-9]

{0,9} means "zero to 9 repetitions of the preceding term", which in this case means "zero to 9 digits".

[0-9] means "a character in the range 0 to 9 (inclusive)", which is the same as \d.

Try:

/^\d+$/

Which means "all numeric input" and excludes blank input.

To allow decimal input too, escape the dot and make the decimal part optional:

/^\d+(\.\d+)?$/

Which means "at least one digit, optionally followed by a dot and at least one digit".

Upvotes: 3

baddger964
baddger964

Reputation: 1227

Use :

  "/^\d*?$/"

\d{0,9} = match 0 to 9 digits

\d* = match 0 to N digits

\d = digit : 0 or 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9

Upvotes: 1

scokmen
scokmen

Reputation: 571

Just remove the {0,9}? and use * instead like

/^\d*$/

{0,9} mean is any length between 0 and 9

Upvotes: 3

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