CODEWITHSUNDEEP
listelixir
sger
sger

Reputation: 740

Elixir command line app with list as parameter

i'm building a simple CLI app with elixir using the following code as my parse function

def parse_args(args) do
 options = OptionParser.parse(args)

 case options do
   {[list: list], _, _} -> [list]
   _ -> :help
 end
end

calling the app with 

./app --list one,two,three

my problem is how to convert comma separated string (binary) into list or any better way to do this.

Upvotes: 0

Views: 687

Answers (1)

Dogbert
Dogbert

Reputation: 222118

You can either split using String.split/2:

iex(1)> {[list: list], _, _} = OptionParser.parse(["--list", "one,two,three"])
{[list: "one,two,three"], [], []}
iex(2)> String.split(list, ",")
["one", "two", "three"]

or use the strict: [list: :keep] option and pass the arguments as ./app --list one --list two --list three:

iex(1)> {parsed, _, _} = OptionParser.parse(["--list", "one", "--list", "two", "--list", "three"], strict: [list: :keep])
{[list: "one", list: "two", list: "three"], [], []}
iex(2)> Keyword.get_values(parsed, :list)
["one", "two", "three"]

I would use the first one unless your strings can contain a comma (in that case you could use another delimiter).

Upvotes: 3

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