Soptareanu Alex
Soptareanu Alex

Reputation: 5206

How to convert an Object {} to an Array [] of key-value pairs in JavaScript

I want to convert an object like this:

{"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}

into an array of key-value pairs like this:

[[1,5],[2,7],[3,0],[4,0]...].

How can I convert an Object to an Array of key-value pairs in JavaScript?

Upvotes: 493

Views: 1667675

Answers (24)

mehmet
mehmet

Reputation: 685

Object to Css Array

var cssObj = {'border-radius':'10px'}
var cssArray = [];

// Converting ...
Object.keys(cssObj).map((key) => {
     cssArray[key] = cssObj[key];
});

console.log(cssArray["border-radius"]);


More data:

You can first convert css object to css array, then simply use it :)

Upvotes: 1

sangram
sangram

Reputation: 415

Sample Input:

var sampleInput={ name: { firstName: "sangram", midddleName: "shivaji", lastName: "Desai", }, address: { street: "Naradawe Road", line1: "near railway station", line2: "behind annapurna hotel", city: "kankavali", pin: "416602", }, };

Sample Output:

var sampleOutput= [ ["name",[ ["firstName","sangram"], ["midddleName","shivaji"], ["lastName","Desai"] ] ], ["address",[ ["street","Naradawe Road"], ["line1","near railway station"], ["line2","behind annapurna hotel"], ["city","kankavali"], ["pin","416602"] ] ] ]

Solution:

const person = { name: { firstName: "sangram", midddleName: "shivaji", lastName: "Desai", }, address: { street: "Naradawe Road", line1: "near railway station", line2: "behind annapurna hotel", city: "kankavali", pin: "416602", }, };

function convertObjectTwoArray(person) {
    let resultArray = [];
    for (let key in person) {
    if ((typeof person[key]).toString() === "object") {
        resultArray.push([key, convertObjectTwoArray(person[key])]);
    } else {
        resultArray.push([key, person[key]]);
    }
    }
    return resultArray;
}

//find result & print
let resultArray = convertObjectTwoArray(person);
console.log( JSON.stringify(resultArray));

Output:

[ ["name",[ ["firstName","sangram"], ["midddleName","shivaji"], ["lastName","Desai"] ] ], ["address",[ ["street","Naradawe Road"], ["line1","near railway station"], ["line2","behind annapurna hotel"], ["city","kankavali"], ["pin","416602"] ] ] ]

Upvotes: 0

Rupam
Rupam

Reputation: 77

const obj = {
  1: 5,
  2: 7,
  3: 0,
  4: 0,
  5: 0,
  6: 0,
  7: 0,
  8: 0,
  9: 0,
  10: 0,
  11: 0,
  12: 0,
};
const arr = [...new Map(Object.entries(obj))];
console.log(arr);

You can convert your Object to Map first and then use the spread operator to convert the Map into an array , arr is now an array of key-value pairs represented as arrays within the map.

Upvotes: -1

Nenad Vracar
Nenad Vracar

Reputation: 122047

You can use Object.keys() and map() to do this

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}
var result = Object.keys(obj).map((key) => [key, obj[key]]);

console.log(result);

Upvotes: 741

yu zhao
yu zhao

Reputation: 9

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5}

result = Object.entries(obj).map((key,value) => [parseInt(key,10), value])

console.log(result);

Upvotes: -1

Dulanjana Abeyrathna
Dulanjana Abeyrathna

Reputation: 91

you can use 3 methods convert object into array (reference for anyone not only for this question (3rd on is the most suitable,answer for this question) Object.keys() ,Object.values(),andObject.entries()

examples for 3 methods

use Object.keys()

const text= {
    quote: 'hello world',
    author: 'unknown'
};
const propertyNames = Object.keys(text);

console.log(propertyNames);
result
[ 'quote', 'author' ]

use Object.values()

const propertyValues = Object.values(text);

console.log(propertyValues);

result

[ 'Hello world', 'unknown' ]

use Object.entires()

const propertyValues = Object.entires(text);

console.log(propertyValues);

result

[ [ 'quote', 'Hello world' ], [ 'author', 'unknown' ] ]

Upvotes: 8

Pila
Pila

Reputation: 5842

The best way is to do:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}
var result = Object.entries(obj);

console.log(result);

Calling entries, as shown here, will return [key, value] pairs, as the caller requested.

Alternatively, you could call Object.values(obj), which would return only values.

Upvotes: 346

Mohamed_Iyed
Mohamed_Iyed

Reputation: 99

or you can use Object.assign():

const obj = { 0: 1, 1: 2, 2: 3};
const arr = Object.assign([], obj);
console.log(arr)
// arr is [1, 2, 3]

Upvotes: 3

KATHEESKUMAR
KATHEESKUMAR

Reputation: 177

const persons = { 
    john: { age: 23, year:2010},
    jack: { age: 22, year:2011},
    jenny: { age: 21, year:2012}
}
const resultArray = Object.keys(persons).map(index => {
    let person = persons[index];
    return person;
});

//use this for not indexed object to change array

Upvotes: 4

Muhammad Shaeel
Muhammad Shaeel

Reputation: 117

var obj = { "1": 5, "2": 7, "3": 0, "4": 0, "5": 0, "6": 0, "7": 0, "8": 0, "9": 0, "10": 0, "11": 0, "12": 0 }
let objectKeys = Object.keys(obj);

let answer = objectKeys.map(value => {
    return [value + ':' + obj[value]]
});

Upvotes: 5

Nageshwar Reddy Pandem
Nageshwar Reddy Pandem

Reputation: 1047

In Ecmascript 6,

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

var res = Object.entries(obj);

console.log(res);

var obj = {
  "1": 5,
  "2": 7,
  "3": 0,
  "4": 0,
  "5": 0,
  "6": 0,
  "7": 0,
  "8": 0,
  "9": 0,
  "10": 0,
  "11": 0,
  "12": 0
};
var res = Object.entries(obj);
console.log(res);

Upvotes: 30

OZZIE
OZZIE

Reputation: 7348

You can use Object.values([]), you might need this polyfill if you don't already:

const objectToValuesPolyfill = (object) => {
  return Object.keys(object).map(key => object[key]);
};
Object.values = Object.values || objectToValuesPolyfill;

https://stackoverflow.com/a/54822153/846348

Then you can just do:

var object = {1: 'hello', 2: 'world'};
var array = Object.values(object);

Just remember that arrays in js can only use numerical keys so if you used something else in the object then those will become `0,1,2...x``

It can be useful to remove duplicates for example if you have a unique key.

var obj = {};
object[uniqueKey] = '...';

Upvotes: 9

Qui-Gon Jinn
Qui-Gon Jinn

Reputation: 4388

This is my solution, i have the same issue and its seems like this solution work for me.

yourObj = [].concat(yourObj);

Upvotes: 3

Nagnath Mungade
Nagnath Mungade

Reputation: 1009

We can change Number to String type for Key like below:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}
var result = Object.keys(obj).map(function(key) {
  return [String(key), obj[key]];
});
    
console.log(result);

Upvotes: 0

bigh_29
bigh_29

Reputation: 2633

Yet another solution if Object.entries won't work for you.

const obj = {
      '1': 29,
      '2': 42
    };
const arr = Array.from(Object.keys(obj), k=>[`${k}`, obj[k]]);
console.log(arr);

Upvotes: 23

Yossi
Yossi

Reputation: 6027

With lodash, in addition to the answer provided above, you can also have the key in the output array.

Without the object keys in the output array

for:

const array = _.values(obj);

If obj is the following:

{ “art”: { id: 1,  title: “aaaa” }, “fiction”: { id: 22,  title: “7777”} }

Then array will be:

[ { id: 1, title: “aaaa” }, { id: 22, title: “7777” } ]

With the object keys in the output array

If you write instead ('genre' is a string that you choose):

const array= _.map(obj, (val, id) => {
    return { ...val, genre: key };
  });

You will get:

[ 
  { id: 1, title: “aaaa” , genre: “art”}, 
  { id: 22, title: “7777”, genre: “fiction” }
]

Upvotes: 8

CarlosH.
CarlosH.

Reputation: 736

To recap some of these answers now on 2018, where ES6 is the standard.

Starting with the object:

let const={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
  • Just blindly getting the values on an array, do not care of the keys:

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.values(obj));
//[9,8,7,6,5,4,3,2,1,0,5]

  • Simple getting the pairs on an array:

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.entries(obj));
//[["1",9],["2",8],["3",7],["4",6],["5",5],["6",4],["7",3],["8",2],["9",1],["10",0],["12",5]]

  • Same as previous, but with numeric keys on each pair:

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.entries(obj).map(([k,v])=>[+k,v]));
//[[1,9],[2,8],[3,7],[4,6],[5,5],[6,4],[7,3],[8,2],[9,1],[10,0],[12,5]]

  • Using the object property as key for a new array (could create sparse arrays):

const obj={"1":9,"2":8,"3":7,"4":6,"5":5,"6":4,"7":3,"8":2,"9":1,"10":0,"12":5};
console.log(Object.entries(obj).reduce((ini,[k,v])=>(ini[k]=v,ini),[]));
//[undefined,9,8,7,6,5,4,3,2,1,0,undefined,5]

This last method, it could also reorganize the array order depending the value of keys. Sometimes this could be the desired behaviour (sometimes don't). But the advantage now is that the values are indexed on the correct array slot, essential and trivial to do searches on it.

  • Map instead of Array

Finally (not part of the original question, but for completeness), if you need to easy search using the key or the value, but you don't want sparse arrays, no duplicates and no reordering without the need to convert to numeric keys (even can access very complex keys), then array (or object) is not what you need. I will recommend Map instead:

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Map

let r=new Map(Object.entries(obj));
r.get("4"); //6
r.has(8); //true

Upvotes: 33

user4639281
user4639281

Reputation:

Object.entries() returns an array whose elements are arrays corresponding to the enumerable property [key, value] pairs found directly upon object. The ordering of the properties is the same as that given by looping over the property values of the object manually.

- https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/entries#Description

The Object.entries function returns almost the exact output you're asking for, except the keys are strings instead of numbers.

const obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

console.log(Object.entries(obj));

If you need the keys to be numbers, you could map the result to a new array with a callback function that replaces the key in each pair with a number coerced from it.

const obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

const toNumericPairs = input => {
    const entries = Object.entries(input);
    return entries.map(entry => Object.assign(entry, { 0: +entry[0] }));
}

console.log(toNumericPairs(obj));

I use an arrow function and Object.assign for the map callback in the example above so that I can keep it in one instruction by leveraging the fact that Object.assign returns the object being assigned to, and a single instruction arrow function's return value is the result of the instruction.

This is equivalent to:

entry => {
    entry[0] = +entry[0];
    return entry;
}

As mentioned by @TravisClarke in the comments, the map function could be shortened to:

entry => [ +entry[0], entry[1] ]

However, that would create a new array for each key-value pair, instead of modifying the existing array in place, hence doubling the amount of key-value pair arrays created. While the original entries array is still accessible, it and its entries will not be garbage collected.

Now, even though using our in-place method still uses two arrays that hold the key-value pairs (the input and the output arrays), the total number of arrays only changes by one. The input and output arrays aren't actually filled with arrays, but rather references to arrays and those references take up a negligible amount of space in memory.

  • Modifying each key-value pair in-place results in a negligible amount of memory growth, but requires typing a few more characters.
  • Creating a new array for each key-value pair results in doubling the amount of memory required, but requires typing a few less characters.

You could go one step further and eliminate growth altogether by modifying the entries array in-place instead of mapping it to a new array:

const obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0};

const toNumericPairs = input => {
  const entries = Object.entries(obj);
  entries.forEach(entry => entry[0] = +entry[0]);
  return entries;
}

console.log(toNumericPairs(obj));

Upvotes: 84

Chopper Lee
Chopper Lee

Reputation: 1577

you can use _.castArray(obj).

example: _.castArray({ 'a': 1 }); // => [{ 'a': 1 }]

Upvotes: -1

Niladri Basu
Niladri Basu

Reputation: 10614

Use Object.entries to get each element of Object in key & value format, then map through them like this:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}

var res = Object.entries(obj).map(([k, v]) => ([Number(k), v]));

console.log(res);

But, if you are certain that the keys will be in progressive order you can use Object.values and Array#map to do something like this:

var obj = {"1":5,"2":7,"3":0,"4":0,"5":0,"6":0,"7":0,"8":0,"9":0,"10":0,"11":0,"12":0}; 

                        // idx is the index, you can use any logic to increment it (starts from 0)
let result = Object.values(obj).map((e, idx) => ([++idx, e]));

console.log(result);

Upvotes: 10

Adam Boostani
Adam Boostani

Reputation: 6247

If you are using lodash, it could be as simple as this:

var arr = _.values(obj);

Upvotes: 7

Marina Lebedeva
Marina Lebedeva

Reputation: 139

Recursive convert object to array

function is_object(mixed_var) {
    if (mixed_var instanceof Array) {
        return false;
    } else {
        return (mixed_var !== null) && (typeof( mixed_var ) == 'object');
    }
}


function objectToArray(obj) {
    var array = [], tempObject;
    for (var key in obj) {

        tempObject = obj[key];

        if (is_object(obj[key])) {
            tempObject = objectToArray(obj[key]);
        }
        array[key] = tempObject;
    }
    return array;
}

Upvotes: 0

wkyniston
wkyniston

Reputation: 1

Use for in

var obj = { "10":5, "2":7, "3":0, "4":0, "5":0, "6":0, "7":0,
            "8":0, "9":0, "10":0, "11":0, "12":0 };

var objectToArray = function(obj) {
    var _arr = [];

    for (var key in obj) {
        _arr.push([key, obj[key]]);
    }
    return _arr;
}

console.log(objectToArray(obj));

Upvotes: 0

Pranav C Balan
Pranav C Balan

Reputation: 115222

Use Object.keys and Array#map methods.

var obj = {
  "1": 5,
  "2": 7,
  "3": 0,
  "4": 0,
  "5": 0,
  "6": 0,
  "7": 0,
  "8": 0,
  "9": 0,
  "10": 0,
  "11": 0,
  "12": 0
};
// get all object property names
var res = Object.keys(obj)
  // iterate over them and generate the array
  .map(function(k) {
    // generate the array element 
    return [+k, obj[k]];
  });

console.log(res);

Upvotes: 10

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