Reputation: 102439
I have some jQuery code. I have called an Ajax function file, file.php, that has some fields, like:
<input type="radio" value="plz">Milk</input>.
Will I assign into again jQuery function? If so, how do I do it? I attached a sample file:
<html>
<head>
<LINK REL=StyleSheet HREF="examples.css" TITLE="Contemporary" TYPE="text/css">
<script src="jquery-1.2.6.js" type="text/javascript"></script>
<script src="jquery-impromptu.1.6.js" type="text/javascript"></script>
<script>
$(document).ready(function(){
$.ajax({
type:"GET",
url:"file.php",
data:id,
success:function(){
var txt=id;
$.prompt( txt,{ opacity: 0.2 });
},
error:function(){
window.location("ERRoR");
}
});
});
</script>
<body>
</body>
</html>
Upvotes: 3
Views: 40759
Reputation: 3188
The success
function takes a parameter, which contains the fetched data. So in your example:
$(document).ready(
function(){ $.ajax({
type:"GET",
url:"file.php",
data:id,
success:function(txt){
$.prompt( txt,{ opacity: 0.2 });
},
// ... more ...
}
});
More examples are in the jQuery documentation.
Upvotes: 12
Reputation: 1
jQuery.ajax({
type:"POST",
url:"file.php",
data:"id1="+val1+"&id2="+val2,
success:function(data){
jQuery("#div_id").html(data);
}
Upvotes: -1