CODEWITHSUNDEEP
javascriptjqueryvalidation
Janith Chinthana
Janith Chinthana

Reputation: 3844

validate input value contain x numbers of numeric characters

I need to validate a input field which should contain at least x number of numeric characters.

eg: let say I need to input value has at least 5 numeric characters

12345 - valid
AB12345 - valid
123456 - valid
AB312312 - valid
asd - not valid
213 - not valid

First I tried with input.length, but I don't know it will have a leading letters or not, so length doesn't help for me

how should I do this validation with jquery or javascript ?

Upvotes: 0

Views: 458

Answers (4)

Miloš Đakonović
Miloš Đakonović

Reputation: 3871

If

inputValue.replace(/[^0-9]/g,"").length < 5

then input field is invalid.

Upvotes: 1

simon
simon

Reputation: 2946

How about something like this 

x = 5;
myString = "AB12345";
if (myString.replace(/[^0-9]/g,"").length >= x) {
    alert('valid');
} else {
    alert('not valid');
}

see this jsfiddle.

Upvotes: 1

Samuel Toh
Samuel Toh

Reputation: 19268

Let say you are looking at validating 5 numeric then you can use regular expression /(?=(?:[\d]){5}).

What this expression does is that;

  1. (?=) means start looking ahead
  2. (?:[\d]) means match digits but don't capture them
  3. {5} means (?:[\d]) (match digit) do 5 times

"use strict";
let numbers = [ '12345', 'ABC12345', '123456', 'AB312312', 'asd', '213'];

numbers.forEach(number=> {
    if (/(?=(?:[\d]){5})/.exec(number)) {
        console.log(number + " is valid.");
    };
});

Upvotes: 1

Jay Ghosh
Jay Ghosh

Reputation: 682

Using regular expressions will do the trick

function check(str,x){
   var pattern = '^[a-zA-Z0-9]*[0-9]{'+x+'}[a-zA-Z0-9]*$';
   if(str.match(pattern)) return true;
   return false;
}

Upvotes: 1

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