CODEWITHSUNDEEP
phpemailcsvphpmailer
John
John

Reputation: 61

How to send csv file in attachment php

I have below code 

$files = array('/home/my_scripts/my_csvfiles/Multiple_Tracking/Multiple_Tracking_Result_Output_'.$date.'.csv','/home/my_scripts/my_csvfiles/Multiple_Tracking/Multiple_Tracking_Result_Not_match_Output_'.$date.'.csv');

$to = "[email protected]";
$from = "[email protected]"; 
$subject ="Multiple Tracking Data Checked Result"; 
$message = "PFA for Multiple Tracking Data Sheet Checked by Script. Date - " . $date ;
$headers = "From: $from";

// boundary 
$semi_rand = md5(time()); 
$mime_boundary = "==Multipart_Boundary_x{$semi_rand}x"; 

// headers for attachment 
$headers .= "\nMIME-Version: 1.0\n" . "Content-Type: multipart/mixed;\n" . " boundary=\"{$mime_boundary}\""; 

// multipart boundary 
$message = "This is a multi-part message in MIME format.\n\n" . "--{$mime_boundary}\n" . "Content-Type: text/plain; charset=\"iso-8859-1\"\n" . "Content-Transfer-Encoding: 7bit\n\n" . $message . "\n\n"; 
$message .= "--{$mime_boundary}\n";

// preparing attachments
for($x=0;$x<count($files);$x++){
    $file = fopen($files[$x],"rb");
    $data = fread($file,filesize($files[$x]));
    fclose($file);
    $data = chunk_split(base64_encode($data));
    $message .= "Content-Type: {\"application/octet-stream\"};\n" . " name=\"$files[$x]\"\n" . 
    "Content-Disposition: attachment;\n" . " filename=\"$files[$x]\"\n" . 
    "Content-Transfer-Encoding: base64\n\n" . $data . "\n\n";
    $message .= "--{$mime_boundary}\n";
}
// send
$ok = @mail($to, $subject, $message, $headers); 
if ($ok) {  echo "Mail sent to $to!";}
else { echo "Mail could not be sent!"; }

but it is sending complete file path as file name in attachments. As I have mention absolute path in $files array. But whenever I put relative path it in array it send empty csv files in email attachment. I just want to send file name in attachment. so is there any solution I can get only file name in with proper data in mail attachment.

Upvotes: 1

Views: 2009

Answers (1)

Michail M.
Michail M.

Reputation: 745

Get filename:

$info = new SplFileInfo($files[$x]);
$fileName = $info->getFilename();

And put it on:

"Content-Disposition: attachment;\n" . " filename=\"$fileName\"\n" .

Upvotes: 1

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