Reputation: 25
I'm using Qt 5.7 and a I have a component that behaves like a QMenuBar. This component has two methods, one, called addMenu(QPushButton* menu)
, to add a bar menu and another, called addMenuItem(QPushButton* menu, QString item, const char *slot)
to add the items that make up one of the bar menus. In this second method, I call addAction method of QMenu, and must pass two arguments to it: the item name and the slot that will run when the item is triggered. My question is how to do it.
I did a search (see here) and I found that QT treat slots as const char *
, but when I try to compile my program using this method signature, it gives error, stating that there is no operator() registered for this type.
My code:
GMInternalMenu::addMenuItem(QPushButton *menu, QString menuItem, const char* slot){
QMenu *dropdown = mapa->value(menu);
dropdown->addAction(menuItem, slot);
}
Using the method:
ui->imMenu->addMenuItem(someButton, "Some action", SLOT(close()));
Output error: (Also on pastebin)
In file included from C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtGui/qwindowdefs.h:43:0,
from C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtWidgets/qwidget.h:43,
from C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtWidgets/qmenu.h:43,
from C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtWidgets/QMenu:1,
from ../Project/mymenu.h:4,
from ../Project/mymenu.cpp:1:
C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtCore/qobject.h: In instantiation of 'static typename QtPrivate::QEnableIf<(QtPrivate::FunctionPointer<Func2>::ArgumentCount == (-1)), QMetaObject::Connection>::Type QObject::connect(const typename QtPrivate::FunctionPointer<Func>::Object*, Func1, const QObject*, Func2, Qt::ConnectionType) [with Func1 = void (QAction::*)(bool); Func2 = const char*; typename QtPrivate::QEnableIf<(QtPrivate::FunctionPointer<Func2>::ArgumentCount == (-1)), QMetaObject::Connection>::Type = QMetaObject::Connection; typename QtPrivate::FunctionPointer<Func>::Object = QAction]':
C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtCore/qobject.h:293:74: required from 'static typename QtPrivate::QEnableIf<(QtPrivate::FunctionPointer<Func2>::ArgumentCount == (-1)), QMetaObject::Connection>::Type QObject::connect(const typename QtPrivate::FunctionPointer<Func>::Object*, Func1, Func2) [with Func1 = void (QAction::*)(bool); Func2 = const char*; typename QtPrivate::QEnableIf<(QtPrivate::FunctionPointer<Func2>::ArgumentCount == (-1)), QMetaObject::Connection>::Type = QMetaObject::Connection; typename QtPrivate::FunctionPointer<Func>::Object = QAction]'
C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtWidgets/qmenu.h:120:9: required from 'QAction* QMenu::addAction(const QString&, Func1, const QKeySequence&) [with Func1 = const char*]'
../Project/mymenu.cpp:35:39: required from here
C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtCore/qglobal.h:746:47: error: static assertion failed: Signal and slot arguments are not compatible.
#define Q_STATIC_ASSERT_X(Condition, Message) static_assert(bool(Condition), Message)
^
C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtCore/qobject.h:306:9: note: in expansion of macro 'Q_STATIC_ASSERT_X'
Q_STATIC_ASSERT_X((FunctorArgumentCount >= 0),
^
In file included from C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtCore/qobjectdefs.h:50:0,
from C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtGui/qwindowdefs.h:44,
from C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtWidgets/qwidget.h:43,
from C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtWidgets/qmenu.h:43,
from C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtWidgets/QMenu:1,
from ../Project/mymenu.h:4,
from ../Project/mymenu.cpp:1:
C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtCore/qobjectdefs_impl.h: In instantiation of 'struct QtPrivate::FunctorReturnType<const char*, QtPrivate::List<> >':
C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtCore/qobject.h:309:158: required from 'static typename QtPrivate::QEnableIf<(QtPrivate::FunctionPointer<Func2>::ArgumentCount == (-1)), QMetaObject::Connection>::Type QObject::connect(const typename QtPrivate::FunctionPointer<Func>::Object*, Func1, const QObject*, Func2, Qt::ConnectionType) [with Func1 = void (QAction::*)(bool); Func2 = const char*; typename QtPrivate::QEnableIf<(QtPrivate::FunctionPointer<Func2>::ArgumentCount == (-1)), QMetaObject::Connection>::Type = QMetaObject::Connection; typename QtPrivate::FunctionPointer<Func>::Object = QAction]'
C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtCore/qobject.h:293:74: required from 'static typename QtPrivate::QEnableIf<(QtPrivate::FunctionPointer<Func2>::ArgumentCount == (-1)), QMetaObject::Connection>::Type QObject::connect(const typename QtPrivate::FunctionPointer<Func>::Object*, Func1, Func2) [with Func1 = void (QAction::*)(bool); Func2 = const char*; typename QtPrivate::QEnableIf<(QtPrivate::FunctionPointer<Func2>::ArgumentCount == (-1)), QMetaObject::Connection>::Type = QMetaObject::Connection; typename QtPrivate::FunctionPointer<Func>::Object = QAction]'
C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtWidgets/qmenu.h:120:9: required from 'QAction* QMenu::addAction(const QString&, Func1, const QKeySequence&) [with Func1 = const char*]'
../Project/mymenu.cpp:35:39: required from here
C:/Qt/Qt5.7.0/5.7/mingw53_32/include/QtCore/qobjectdefs_impl.h:632:78: error: request for member 'operator()' in 'QtPrivate::FunctorReturnType<Functor, QtPrivate::List<Tail ...> >::dummy<const char*>()', which is of non-class type 'const char*'
typedef decltype(dummy<Functor>().operator()((dummy<ArgList>())...)) Value;
Upvotes: 0
Views: 2938
Reputation: 37606
Here is the declaration of the QMenu::addAction
method you are trying to use:
QAction* addAction(const QString &text,
const QObject *receiver,
const char *member,
const QKeySequence &shortcut = 0);
As you can see, you are missing the receiver
parameter, which is the object that will receive the signal.
From your code, I guess you should have something like:
GMInternalMenu::addMenuItem(QPushButton *menu, QString menuItem,
QObject *receiver, const char* slot){
QMenu *dropdown = mapa->value(menu);
dropdown->addAction(menuItem, receiver, slot);
}
And then when you use it:
ui->imMenu->addMenuItem(someButton, "Some action", this, SLOT(close()));
// ^^^^
// Maybe something else... I do not know
// which object should receive the signal.
Upvotes: 4