CODEWITHSUNDEEP
bash
paul_h
paul_h

Reputation: 2051

Calculating the size of a list of files without using find / -exec

Sure, find -exec allows me to used stat to get file size, and a tiny Python one-liner to sum that:

find . -name "*.sh" -exec stat -f '%z' {} \; | python -c'import sys; print sum(int(x) for x in sys.stdin)'

There could be a use of bc, I guess, to make that more bash-like.

However, (The question), I already have a list of files, find -exec is out. How do I tersely and elegantly get the file sizes in a pipe. I could use a xargs and du|cut pipeline, but despite -s on xargs, I run the risk of blowing up the command length or having to over-allocate to the tune of gigabytes.

I'm hoping for something that can calculate disk usage and do so in a standard-in centric way:

cat myList.txt -exec stat -f '%z' {} \; | python -c'import sys; print sum(int(x) for x in sys.stdin)'

Cat doesn't have an -exec though :-(

Upvotes: 1

Views: 101

Answers (1)

hek2mgl
hek2mgl

Reputation: 158020

You can use a pipe with xargs du and awk:

xargs -a file.list du -b | awk '{t+=$1}END{print t}'

That gives you the accumulated size in bytes.

Upvotes: 2

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