Reputation: 323
$("button.filters").click(function(){
$("div.second").slideToggle("slow");
});
.main {
position: relative;
display:block;
height: 320px;
color: #fff;
background-color: grey;
}
.first {
position: absolute;
bottom: 15%;
height: 70px;
background-color: white;
}
.second {
position: absolute;
bottom: 0%;
height: 30px;
background-color: green;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="main">
<div class="first">
<p>some content</p>
<button class="filters">filters</button>
</div>
<div class="second">
<p>other content</p>
</div>
</div>
Please check this fiddle https://jsfiddle.net/6d1t5jr8/
I need help to make .second div to .slideToggle
from bottom border of .first
div.
Upvotes: 0
Views: 426
Reputation: 29249
The problem:
Because of the bottom:0
in that way, the the height of the .second
div start from the bottom.
The solution:
Try to wrap the .second
with wrapper. So the slide animation will start from the top.
Like this:
jQuery(document).ready(function () {
$("button.filters").click(function(){
$("div.second").slideToggle("slow");
});
});
.main {
position: relative;
display:block;
height: 320px;
color: #fff;
background-color: grey;
}
.first {
position: absolute;
bottom: 15%;
height: 70px;
background-color: white;
}
.second-wrapper {
position: absolute;
bottom: 0%;
height: 30px;
}
.second {
display:none;
background-color: green;
}
.second p {
margin:0;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="main">
<div class="first">
<p>some content</p>
<button class="filters">filters</button>
</div>
<div class="second-wrapper">
<div class="second">
<p>other content</p>
</div>
</div>
</div>
Upvotes: 1