CODEWITHSUNDEEP
filepython-3.x
Allexj
Allexj

Reputation: 1487

How to open multiple files in a directory

I need to build a simple script in python3 that opens more files inside a directory and see if inside these files is a keyword.

All the files inside the directory are like this: "f*.formatoffile" (* stays for a casual number)

Example:

f9993546.txt
f10916138.txt
f6325802.txt

Obviusly i just need to open the txt files ones.

Thanks in advance!

Final script:

import os

Path = "path of files"
filelist = os.listdir(Path)
for x in filelist:
    if x.endswith(".txt"):
        try:
            with open(Path + x, "r", encoding="ascii") as y:
                for line in y:
                    if "firefox" in line:
                        print ("Found in %s !" % (x))
        except:
            pass

Upvotes: 0

Views: 31097

Answers (1)

EndermanAPM
EndermanAPM

Reputation: 347

This should do the trick:

import os
Path = "path of the txt files"
filelist = os.listdir(Path)
for i in filelist:
    if i.endswith(".txt"):  # You could also add "and i.startswith('f')
        with open(Path + i, 'r') as f:
            for line in f:
                # Here you can check (with regex, if, or whatever if the keyword is in the document.)

Upvotes: 6

Related Questions