CODEWITHSUNDEEP
c#wpfxaml
user6729899
user6729899

Reputation:

MultiValueConverter object[] ConvertBack

I am working on converter, I am very new. I don't know, how to get the value from xaml binding. May be will write my code.

In my convertback code I am bit confused. For Double B, I need the value of B inXAML

<TextBlock Text="Offset X [px]"
           Style="{StaticResource StdTextBlockStyle}" />
    <TextBox x:Uid="TextBox_1" 
             Style="{StaticResource StdTextBoxStyle}" >
        <TextBox.Text>
            <MultiBinding Converter="{StaticResource Conv}">
                <Binding Path="B" />
                <Binding Path="A" />
            </MultiBinding>
        </TextBox.Text>
   </TextBox>
<TextBlock />

//C# Code //

    public object Convert(object[] values, Type targetType, object parameter, CultureInfo culture)
    {
       double B = (double)values[0];
       double A = (double)values[1];
       double C = A-B;
       return C;
    }

    public object[] ConvertBack(object value, Type[] targetTypes, object parameter, CultureInfo culture)
       {

            double C = (double)value;    
            double B = // I DON'T KNOW HOW TO GET VALUE FOR B. B is from XAML// ???

            object[] ret = new object[1];    
            ret[0] = C + B;
            return ret;

Upvotes: 0

Views: 700

Answers (1)

Mr.B
Mr.B

Reputation: 3797

You should understand, that result in ConvertBack it is combination of

 double B = (double)values[0];
 double A = (double)values[1];

you defined in Convert. The main idea of Conversion in MultiValueConverter is definition of your own logic how do you want to see these values. That means you need to define your logic to calculate this array. According to your Convert function: 

double C = A-B;

We have in ConvertBack:

double B=A-C;
double A=C+B;

We cannot calculate A and B to define 

Array[] x = new []{ A, B };

Because we have here equalation with 2 unknown variables. Sorry, I don't believe this expression is convertible back.

Upvotes: 1

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