CODEWITHSUNDEEP
arraysruby
Tristan
Tristan

Reputation: 371

Can I iterate through an array of arrays and compare it to an array of integers

I have an array of arrays [[1,2,3],[4,5,6],[7,8,9]]. I also have an array of integers [3,4,5,6,8].

Is it possible for me to check if my integers match a complete array in the array of arrays?

So I have 4,5,6 in the int array, and it matches the middle array [4,5,6].

Upvotes: 2

Views: 91

Answers (4)

webster
webster

Reputation: 4032

Try this:

array_1 = [[1,2,3],[4,5,6],[7,8,9]]
array_2 = [3,4,5,6,8]

array_1.any? { |e| (e - array_2).empty? }
# => true

Upvotes: 1

zhon
zhon

Reputation: 1630

Assuming you expect a true or false and order doesn't matter, the following works:

require 'set'

a1 = [[1,2,3],[4,5,6],[7,8,9]]
a2 = [3,4,5,6,8]

a1.any? { |item| item.to_set.subset? a2.to_set } #=> true

Assuming you want the index into a1 or nil

a1.index { |item| item.to_set.subset? a2.to_set }

Assuming you want the subset itself or nil

index = a1.index { |item| item.to_set.subset? a2.to_set }
index && a1[index]

Upvotes: 0

Ursus
Ursus

Reputation: 30056

This should work

a = [[1,2,3],[4,5,6],[7,8,9]]
integers = [3,4,5,6,8]

a.any? { |sub_array| sub_array.all? { |item| integers.include? item } }

Upvotes: 2

guitarman
guitarman

Reputation: 3310

array1 = [[1,2,3],[4,5,6],[7,8,9]]
array2 = [4,5,6]

result = array1.map{|inner_array| inner_array - array2}
# => [[1, 2, 3], [], [7, 8, 9]]

result.any?{|inner_array| inner_array.empty?}
# => true

Upvotes: 0

Related Questions