Reputation: 4581
What I'm trying to do is SELECT metadata->name, metadata->namespace
but only if the spec.volumes
contains an object with secretName = 'test-secret'
from a list of objects that look like this:
{
"kind": "PodList",
"apiVersion": "v1",
"metadata": {
"selfLink": "/api/v1/pods",
},
"items": [
{
"metadata": {
"name": "pod1",
"namespace": "namespace1"
},
"spec": {
"volumes": [
{
"name": "default-token",
"secret": {
"secretName": "default-token"
}
}
],
"nodeName": "node-1"
}
}
{
"metadata": {
"name": "pod2",
"namespace": "namespace2"
},
"spec": {
"volumes": [
{
"name": "default-token",
"secret": {
"secretName": "default-token"
}
}
],
"nodeName": "node-2"
}
},
{
"metadata": {
"name": "chosen-pod",
"namespace": "namespace3",
},
"spec": {
"volumes": [
{
"name": "pod-storage",
},
{
"name": "test-data",
"secret": {
"secretName": "test-secret"
}
}
],
"nodeName": "node-2",
}
}
]
}
This list is inserted into a table;
CREATE TABLE pods (node TEXT, metadata Object, spec Object)
I think this is the closest I've come;
SELECT metadata->name, metadata->namespace, spec->volumes AS volumes FROM pods WHERE (SELECT COUNT(*) FROM ? WHERE secret->secretName = 'test-data') > 0
But this throws an error:
TypeError: Cannot read property '0' of undefined
at Object.eval [as datafn] (eval at <anonymous> (~/Documents/myproject/node_modules/alasql/dist/alasql.fs.js:7487:20), <anonymous>:3:40)
at ~/Documents/myproject/node_modules/alasql/dist/alasql.fs.js:6100:19
at Array.forEach (native)
at queryfn (~/Documents/myproject/node_modules/alasql/dist/alasql.fs.js:6097:16)
at Array.statement (~/Documents/myproject/node_modules/alasql/dist/alasql.fs.js:7121:14)
at eval [as wherefn] (eval at <anonymous> (~/Documents/myproject/node_modules/alasql/dist/alasql.fs.js:7899:11), <anonymous>:3:56)
at doJoin (~/Documents/myproject/node_modules/alasql/dist/alasql.fs.js:6615:12)
at doJoin (~/Documents/myproject/node_modules/alasql/dist/alasql.fs.js:6687:8)
at queryfn3 (~/Documents/myproject/node_modules/alasql/dist/alasql.fs.js:6174:2)
at queryfn2 (~/Documents/myproject/node_modules/alasql/dist/alasql.fs.js:6149:9)
Hmm, is there an error in my WHERE
clause? No, removing > 0
from the end and it throws the same exception.
Working backwards from this question/ answer I also tried;
SEARCH / AS @a
UNION ALL(
spec->volumes AS @v
RETURN(@a->metadata->name AS name,
@a->metadata->namespace AS namespace,
@v->secret->secretName AS [secretNames]
)
)
FROM pods
But the @v->secret->secretName AS [secretNames]
just yields undefined
;
[ 'pod1', 'namespace1', undefined ]
[ 'pod2', 'namespace2', undefined ]
[ 'chosen-pod', 'namespace3', undefined ]
Returning the naked @v
array puts me right back where I was before--a row with an array that I can't seem to filter against.
Upvotes: 2
Views: 2085
Reputation: 4107
The problem is in spec->volumes
. It is an array, so you need to change the query to @v->0->secret->secretName
:
SEARCH / AS @a
UNION ALL(
spec->volumes AS @v
RETURN(@a->metadata->name AS name,
@a->metadata->namespace AS namespace,
@v->0->secret->secretName AS [secretNames]
)
)
FROM pods
To extract the required elements, please try this code:
const data = {...data...};
let res = alasql('SEARCH items / AS @a \
spec volumes / WHERE(name="test-data") \
RETURN(@a->metadata->name AS name, \
@a->metadata->namespace AS namespace \
) FROM ?',[data]);
Here spec volumes /
loop over all elements of array spec.volumes[]
.
Upvotes: 1