CODEWITHSUNDEEP
java
Abhishekstudent
Abhishekstudent

Reputation: 111

Why does it say that the variable was not initialised?

package mmm;
import java.util.Scanner;
public class Hi{
    public static void main(String args[]){
        int num1, num2, result, choice;
        Scanner abhi = new Scanner(System.in);
        System.out.println("You Have The Following Choices:");
        System.out.println("1. Addition");
        System.out.println("2. Subtraction");
        System.out.println("3. Multiplication");
        System.out.println("4. Division ");

        choice = abhi.nextInt();
        System.out.println("Enter The First Number");
        num1 = abhi.nextInt();
        System.out.println("Enter The Second Number");
        num2 = abhi.nextInt();
        switch(choice){
        case 1:
            result = num1 + num2;
        break;
        case 2:
            result = num1 - num2;
        break;
        case 3:
            result = num1 * num2;
        break;
        case 4:
            result = num1 / num2;
        break;
        default:
            System.out.println("Error");


        }
        System.out.println("The Result Is "+result);



    }
}

It says result was not initialised; whereas I initialised it. Where did I basically go wrong? I declared the variable type and all and did everything I could. I am a noob, so, pardon my silly questions and queries. Any help would be appreciated!

Upvotes: 0

Views: 65

Answers (4)

Kevyn Meganck
Kevyn Meganck

Reputation: 609

If you go in the default case of your switch, the result variable will have received nothing when trying to print it.

You will have to give it a default value either before going in your switch, or inside your default case.

Upvotes: 1

Rudziankoŭ
Rudziankoŭ

Reputation: 11251

Change you first line in the main method as following:

int num1, num2, result, choice = 0;

Upvotes: 0

Mike
Mike

Reputation: 8355

As pointed out by comments.

The variable result is only gets value in cases choice was 1, 2, 3 or 4. So, not all code paths lead to the variable result being assigned to a value.

However, all code paths lead to System.out.println("The Result Is "+result);.

You either have to assign a value to result in the default case, or initialize it with a value at the when declaring it. . .

Upvotes: 1

dunni
dunni

Reputation: 44555

Local variables don't have a default value. You have to initialize the variables int num1, num2, result, choice; with one, if you want to access them.

Upvotes: 1

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