CODEWITHSUNDEEP
pythonregex
tadamhicks
tadamhicks

Reputation: 925

Python regex get substring after preceding substring match

Text has no spaces, so I cannot split at all and use indexing on a list of strings.

The pattern I am looking for is:

check=

It is followed by a number and encoded querystring items (apache logfile) and is on every line of the file twice. I want output that gives me just what follows check=

For instance, the string in a line looks like:

11.249.222.103 - - [15/Aug/2016:13:17:56 -0600] "GET /next2/120005079807?check=37593467%2CCOB&check=37593378%2CUAP&box=match&submit=Next HTTP/1.1" 500 1633 "https://mvt.squaretwofinancial.com/newmed/?button=All&submit=Submit" "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:45.0) Gecko/20100101 Firefox/45.0"

And I need to fetch 37593467 and 37593378 in this case.

Upvotes: 0

Views: 58

Answers (1)

Dinesh Pundkar
Dinesh Pundkar

Reputation: 4196

Please check this code.

import re

text = '''11.249.222.103 - - [15/Aug/2016:13:17:56 -0600] "GET /next2/120005079807?check=37593467%2CCOB&check=37593378%2CUAP&box=match&submit=Next HTTP/1.1" 500 1633 "https://mvt.squaretwofinancial.com/newmed/?button=All&submit=Submit" "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:45.0) Gecko/20100101 Firefox/45.0"'''


for match in re.findall("check=(\d+)",text):
    print 'Found "%s"' % match

Output:

C:\Users\dinesh_pundkar\Desktop>python demo.py
Found "37593467"
Found "37593378"

Couple of URLs for help :

Upvotes: 2

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