CODEWITHSUNDEEP
xcodeswift3xcode8-beta6
Jason Hocker
Jason Hocker

Reputation: 7067

Xcode 8 beta 6 swift 3 localizedCaseInsensitiveCompare

This code was compiling on Xcode 8 beta 5 but broken in beta 6. What is the right new Swift 3 way to do this comparison? 

self.categories = categories.sorted { $0.localizedCaseInsensitiveCompare($1) == ComparisonResult.orderedDescending }

The error is

Argument passes to call that takes no arguments

Upvotes: 1

Views: 1120

Answers (2)

bentz123
bentz123

Reputation: 1121

Same issue here. I tried to compile a snippet from the official Swift 3 guide in Xcode beta and got the same error - Argument passes to call that takes no arguments. Though, when I used IBM Swift Sandbox, it compiled successfully.

let names = ["Chris", "Alex", "Ewa", "Barry", "Daniella"]
func backward(_ s1: String, _ s2: String) -> Bool {
return s1 > s2
}
var reversedNames = names.sorted(by: backward)

From looking here, it seems that the API of sorted changed from x.sorted(isOrderedBefore: >) to x.sorted(by: >). I guess that in the future Xcode beta, this will be taken care of.

Upvotes: 1

OOPer
OOPer

Reputation: 47886

I just have succeeded to get the same error message.

In my testing code, if I declare the instance property categories as:

var categories: [NSString] = []

I have got this error message:

error: argument passed to call that takes no arguments

If your case is very similar to this, you need to change the property declaration to:

var categories: [String] = []

Even if this does not fit for your issue, you'd better check this sort of type-mismatching, because as of Swift 3/Xcode 8 beta 6:

  • Bridging conversions are no longer implicit. The conversion from a Swift value type to its corresponding object can be forced with as. For example: string as NSString. Any Swift value can also be converted to its boxed id representation with as AnyObject. (SE-0072)

(Taken from the Release Notes of Xcode 8 beta 6.)

Upvotes: 1

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