Reputation: 17468
there is no error in the following code.
package main
import (
"fmt"
"math"
)
type ErrNegativeSqrt float64
func (e ErrNegativeSqrt) Error() string {
return fmt.Sprintf("cannot Sqrt negative number: %v", float64(e))
}
func Sqrt(x float64) (float64, error) {
if x < 0 {
err := ErrNegativeSqrt(x)
return x, err
}
z := x
var delta = 1e-10
for {
n := z - (z*z - x) / (2*z)
if math.Abs(n - z) < delta {
break
}
z = n
}
return z, nil
}
func main() {
fmt.Println(Sqrt(2))
fmt.Println(Sqrt(-3))
}
But when I change the for loop in func Sqrt()
, it led to infinite loop?
func Sqrt(x float64) (float64, error) {
if x < 0 {
err := ErrNegativeSqrt(x)
return x, err
}
z := x
var delta = 1e-10
for {
n := z - (z*z - x) / (2*z)
if math.Abs(n - z) < delta {
z = n // here ....
break // break here
}
}
return z, nil
}
Why there are different?
Upvotes: 0
Views: 2027
Reputation: 9116
The second loop will be infinite since the logic is flawed. In this code:
for {
n := z - (z*z - x) / (2*z)
if math.Abs(n - z) < delta {
z = n // here ....
break // break here
}
}
value of z
never updates to the newly calculated value. This results in n := z - (z*z - x) / (2*z)
always working on the same z
, that is equal to x
, since the condition math.Abs(n - z) < delta
never gets to be true.
You need to assign to z
again so it gets updated. You can check this by logging value of z
in the loop. Example code: https://play.golang.org/p/9H7Uze4gip
Upvotes: 4