CODEWITHSUNDEEP
pythondictionarypickle
Senor Penguin
Senor Penguin

Reputation: 405

How to put pickle dict value into an object

I am using pickle to dump a dictionary object into a txt file. I need to grab the dictionary from the file and extract only certain values and put them inside of an object as a string.

My dictionary looks something like this:

obj_dict = { 'name': 'MYID', 'value': 'usdf23444', 
             'name': 'MYID2', 'value' : 'asdfh3479' }

Part of the dilemma I have is that there are two 'name' and two 'value' in the dictionary and I need to grab each separately.

Here is the code I am using:

import pickle

filepath = file.txt
output = open(filepath, 'rb')
obj_dict = pickle.load(output)
for i in obj_dict:
    NewString = "VALUE1=" + i['value1'] + "VALUE2=" + i['value2']

print(NewString)

I know this code doesn't work, I'm more showing what I need my end result to look like but basically I need each value to be put into a string that I can use later. How can I reference 'value1' and 'value2' correctly? Also I am getting this error when trying to just get one 'value': TypeError: list indices must be integers or slices, not str

EDIT FOR COMMENT 2

I'm not sure if that's true, I can run this code:

output = open(filepath, 'rb')
obj_dict = pickle.load(output)
for i in obj_dict:
    print(i['value'])

and my output is:

usdf23444
asdfh3479

Upvotes: 0

Views: 758

Answers (1)

bananafish
bananafish

Reputation: 2917

After the update, it looks like it is a list of dicts. Try:

strings = ["VALUE{}={}".format(i, d['value']) for i, d in enumerate(obj_dict)]

Upvotes: 1

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