CODEWITHSUNDEEP
scalajson4s
arosca
arosca

Reputation: 537

How do I generate pretty JSON with json4s?

This snippet of code works very well, but it generates compact JSON (no line breaks / not very human readable).

import org.json4s.native.Serialization.write
implicit val jsonFormats = DefaultFormats

//snapshotList is a case class
val jsonString: String = write(snapshotList)

Is there an easy way to generate pretty JSON from this?

I have this workaround but I'm wondering if a more efficient way exists:

import org.json4s.jackson.JsonMethods._
val prettyJsonString = pretty(render(parse(jsonString)))

Upvotes: 7

Views: 6333

Answers (2)

Michael Pollmeier
Michael Pollmeier

Reputation: 1380

import org.json4s.jackson.Serialization.writePretty

val jsonString: String = writePretty(snapshotList)

Upvotes: 16

Nathaniel Ford
Nathaniel Ford

Reputation: 21220

You can use the ObjectMapper writerWithDefaultPrettyPrinter function:

ObjectMapper mapper = new ObjectMapper();
val pretty = mapper.writerWithDefaultPrettyPrinter()
                   .writeValueAsString(jsonString));

This returns a ObjectWriter object from which you can get a pretty-formatted string.

Upvotes: 0

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