CODEWITHSUNDEEP
javascriptjqueryangularjsjson
user1005310
user1005310

Reputation: 877

Nested JSON, remove object based on a condition in Jquery using angularjs

I have a JSON object in this variable $scope.bbTreeData. I am trying to remove the object where flag is false. I am able to traverse through the nested JSON object but I am not sure how to remove the object ? any suggestion ?

[{
  "market": "Atl",
  "subItem": [{
    "comment_id": "1",
    "user_id": "32509",
    "flag": true
  }, {
    "comment_id": "2",
    "user_id": "32510",
    "flag": false

  }]
}, {
  "market": "Chicago",
  "subItem": [{
    "comment_id": "3",
    "user_id": "32501",
    "flag": true
  }, {
    "comment_id": "4",
    "user_id": "32502",
    "flag": false

  }]
}]

$scope.bbTreeInactiveData = angular.copy($scope.bbTreeData);
angular.forEach($scope.bbTreeInactiveData, function(item) {
  angular.forEach(item.subItem, function(record, index) {
    if (record.flag == false) {
      console.log(item.subItem, index);
      /* code to remove the object*/
    }
  });
});

Upvotes: 1

Views: 1765

Answers (3)

Mohan Dere
Mohan Dere

Reputation: 4597

Try this: 

$scope.bbTreeInactiveData = angular.copy($scope.bbTreeData);

var results = $scope.bbTreeInactiveData.map(function(row) {
  return row.subItem.filter(function(cell) {
    return cell.flag == true
  });
});

Use map() and filter() function.

Upvotes: 1

Pop-A-Stash
Pop-A-Stash

Reputation: 6652

You can use the delete keyword in plain JavaScript:

delete item.subItem[index]

Which I believe there is already an answer for: How do I remove a property from a JavaScript object?

If you want to delete the root, add an index parameter to your first forEach, then delete the root with array splice function:

$scope.bbTreeInactiveData.splice(indexRoot,1);

Upvotes: 0

Raman Sahasi
Raman Sahasi

Reputation: 31851

You can use _without() function of _underscorejs

see the documentation

without
_.without(array, values)

Returns a copy of the array with all instances of the values removed.

_.without([1, 2, 1, 0, 3, 1, 4], 0, 1);
=> [2, 3, 4]

Input

[
    {
        "market": "Atl",
        "subItem": [
            {
                "comment_id": "1",
                "user_id": "32509",
                "flag": true
            },
            {
                "comment_id": "2",
                "user_id": "32510",
                "flag": false
            }
        ]
    },
    {
        "market": "Chicago",
        "subItem": [
            {
                "comment_id": "3",
                "user_id": "32501",
                "flag": true
            },
            {
                "comment_id": "4",
                "user_id": "32502",
                "flag": false
            }
        ]
    }
]

Output

[
    {
        "market": "Atl",
        "subItem": [
            {
                "comment_id": "1",
                "user_id": "32509",
                "flag": true
            }
        ]
    },
    {
        "market": "Chicago",
        "subItem": [
            {
                "comment_id": "3",
                "user_id": "32501",
                "flag": true
            }
        ]
    }
]

Code Snippet

var json = JSON.parse('[{"market":"Atl","subItem":[{"comment_id":"1","user_id":"32509","flag":true},{"comment_id":"2","user_id":"32510","flag":false}]},{"market":"Chicago","subItem":[{"comment_id":"3","user_id":"32501","flag":true},{"comment_id":"4","user_id":"32502","flag":false}]}]');

for(var i=0; i<json.length; i++) {
    json[i].subItem = _.without(json[i].subItem, _.findWhere(json[i].subItem, {flag: false}));
};

console.log(JSON.stringify(json, 0, 8));
<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.3/underscore-min.js"></script>

Upvotes: 2

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