Reputation: 21
I'm doing a program with graphical interface using PyQt5 . I want to do is that when the user presses certain button, this change widget and show other options.
For this I decided to use QStackedWidget, and all my interface build it from the QT5 designer.
However, in my code, wanting to determine that my name button "btfr" show me "page_2" of my stackedWidget when pressed, using the QStackedWidget.setCurrentIndex method, this does nothing or make any error.
the code is as follows:
import sys
from PyQt5 import uic
from PyQt5.QtCore import QTimeLine
from PyQt5.QtWidgets import *
from PyQt5.QtGui import *
infz = uic.loadUiType("main.ui")[0]
class FaderWidget(QWidget):
def __init__(self, old_widget, new_widget):
QWidget.__init__(self, new_widget)
self.old_pixmap = QPixmap(new_widget.size())
old_widget.render(self.old_pixmap)
self.pixmap_opacity = 1.0
self.timeline = QTimeLine()
self.timeline.valueChanged.connect(self.animate)
self.timeline.finished.connect(self.close)
self.timeline.setDuration(333)
self.timeline.start()
self.resize(new_widget.size())
self.show()
def paintEvent(self, event):
painter = QPainter()
painter.begin(self)
painter.setOpacity(self.pixmap_opacity)
painter.drawPixmap(0, 0, self.old_pixmap)
painter.end()
def animate(self, value):
self.pixmap_opacity = 1.0 - value
self.repaint()
class StackedWidget(QStackedWidget):
def __init__(self, parent=None):
QStackedWidget.__init__(self, parent)
def setCurrentIndex(self, index):
self.stack = MyWindowClass()
self.a = self.stack.stackedWidget.currentWidget()
self.b = self.stack.stackedWidget.widget(index)
self.fader_widget = FaderWidget(self.a, self.b)
QStackedWidget.setCurrentIndex(self, index)
print(self, index)
def setPage1(self):
self.setCurrentIndex(0)
def setPage2(self):
self.setCurrentIndex(1)
class MyWindowClass(QStackedWidget, infz):
def __init__(self, parent=None):
global pos, c, f
self.pos = 0
self.c = []
self.f = False
QStackedWidget.__init__(self, parent)
self.setupUi(self)
self.setWindowTitle('SkR')
if __name__ == "__main__":
app = QApplication(sys.argv)
window = MyWindowClass()
window.resize(788, 518)
stack = StackedWidget()
window.btfr.clicked.connect(stack.setPage2)
window.btnpx.clicked.connect(stack.setPage1)
window.show()
sys.exit(app.exec_())
What I intend with this code is that the change of widget does so with an effect: "fade out".
If I print the "self " and the "index " receiving QStackedWidget.setCurrentIndex shows the following:
<__main__.StackedWidget object at 0x7fc2eb6b5c18> 0
The number zero is index, and the other element is self
Thank you for your attention, I hope someone can help.
Upvotes: 2
Views: 3656
Reputation: 8999
Your question isn't completely clear, but don't you just want:
def setIndex(self, index):
self.setCurrentIndex(index)
However, this is a little redundant as you should able to link the button directly to the setCurrentIndex
method and use lambda
to pass the index value:
btfr.clicked.connect(lambda: self.setCurrentIndex(2))
Upvotes: 2