Reputation: 1793
Function constrain
of the R package diversitree takes a list of formulae as input.
formulae <- list(lambda1 ~ lambda0, mu1 ~ mu0, q10 ~ q01)
constrain(lik, formulae=formulae)
I would like to pass these formulae via a decision tree and concatenate them as needed.
f1 <- "lambda1 ~ lambda0"
f2 <- "mu1 ~ mu0"
f3 <- "q10 ~ q01"
How do I arrive at the above-shown list formulae
?
Unsuccessful attempt:
formulae <- as.formula(paste(f1,f2,f3, collapse=","))
EDIT 1:
I do not know the precise number of respective formulae a prior, but let them be determined via a decision tree. The precise number of individual formulae (i.e., f1
, f2
, f3
, etc.) that goes into variable formulae
should thus not be hard-coded.
Upvotes: 2
Views: 1286
Reputation: 73385
You can use:
formulae = list(as.formula(f1),as.formula(f2),as.formula(f3))
If you originally have all string formulae in a vector, say f <- c(f1, f2, f3)
, you may use
lapply(f, as.formula)
Upvotes: 2