Reputation: 2963
I have a Pandas dataframe df
that looks like this:
A B
1 1 [a,b,d,d]
2 6 [,1,4,d,g]
3 a [w,1,NaN,x,y,2]
I need to remove the blank in row 2, and the NaN in row 3 to get:
A B
1 1 [a,b,d,d]
2 6 [1,4,d,g]
3 a [w,1,x,y,2]
I think applying some kind of lambda list comprehension?
df.B=df.B.apply(lambda x: x if x not in ['',np.NaN])
but not working...
Upvotes: 1
Views: 291
Reputation: 16251
You need to work on your comprehension skills :)
import numpy as np
df = pd.DataFrame([
[1, ['a','b','d','d']],
[6, ['',1,4,'d','g']],
['a', ['w',1,np.nan,'x','y',2]]
], columns=['A', 'B'])
df.B.apply(lambda l: [x for x in l if x not in ['', np.nan]])
where l
is the current list and x
are elements of l
.
Upvotes: 3