CODEWITHSUNDEEP
javascriptregexstringurlreplace
SaphuA
SaphuA

Reputation: 3130

Get everything except match in javascript regular expression

I have the following regex to get the first part after a url:

^http[s]?:\/\/.*?\/([a-zA-Z-_.%]+).*$

It matches test in the below urls:

foo.com
http://foo.com
http://foo.com/test
http://foo.com/test/
http://foo.com/test?bar

What I'm now trying to do is recreate the same url, but replace test with a different value. Either by taking the parts before and after the match or reversing the result.

I'm sure there's a regexy way of doing this, but I'm unable to find out how to do so.

Upvotes: 0

Views: 229

Answers (1)

anubhava
anubhava

Reputation: 784898

You can use a capturing group for part before /test and use it as back-reference in replacement:

var re = /^(https?:\/\/[^\/]+\/)[^?\/]+/gmi; 
var subst = '$1foobar'; 

var result = str.replace(re, subst);

[^?\/]+ will match text before next / or ? after domain name in URL. As your original regex it also assumes that URLs start with http:// or https://.

RegEx Demo

Upvotes: 2

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