CODEWITHSUNDEEP
xmlxsltxml-parsingxslt-1.0
sandunes90
sandunes90

Reputation: 473

How to call a custom replace function twice in XSLT 1.0?

I need to convert an input string - 

10:05:30.00

to 

10053000

that is to replace the ":" and the "." characters.

I referred to this answer - XSLT string replace

and added the replace function.

Now I can call it once like this -

<xsl:call-template name="replace-string">
                            <xsl:with-param name="text" select="fruits/apples"/>
                            <xsl:with-param name="replace" select="':'" />
                            <xsl:with-param name="with" select="''"/>
                          </xsl:call-template>

and it returns this value - 

100530.00

How can I call it again where I can specify my replace string as "." so that this character is removed. Please note I have to use XSLT 1.0 so I don't have access to the replace() function in XSLT 2.0.

Upvotes: 1

Views: 308

Answers (1)

michael.hor257k
michael.hor257k

Reputation: 117073

Why don't you do simply: 

translate ($string, ':.', '')

To actually replace multiple substrings (with more than one character each), your recursive template would have to do two nested loops - with the outer loop tokenizing the search-strings and/or the replace-strings parameter.

Upvotes: 4

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