CODEWITHSUNDEEP
c++winapi
kaykun
kaykun

Reputation: 2267

GetOpenFileName Program-Defined Directory

I want to create a dialog box that resembles the one created with GetOpenFileDialog. However, I want the dialog to display a list of filenames that the program provides, and these filenames don't necessarily exist as files in a directory. The purpose is to provide a dialog with a similar look and feel for opening files, but rather inside of a zip file which the program would extract after selection. So, is there any way this is possible?

Upvotes: 0

Views: 196

Answers (1)

casablanca
casablanca

Reputation: 70691

No, you'll have to write one yourself. You can however find the common dialog box templates in the PlatformSDK\Include directory; you can use the FileOpen.dlg template to build a dialog similar to the standard Open dialog.

Upvotes: 2

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