CODEWITHSUNDEEP
javakotlinmodelmapper
sunnyone
sunnyone

Reputation: 1530

Better way to map Kotlin data objects to data objects

I want to convert/map some "data" class objects to similar "data" class objects. For example, classes for web form to classes for database records.

data class PersonForm(
    val firstName: String,
    val lastName: String,
    val age: Int,
    // maybe many fields exist here like address, card number, etc.
    val tel: String
)
// maps to ...
data class PersonRecord(
    val name: String, // "${firstName} ${lastName}"
    val age: Int, // copy of age
    // maybe many fields exist here like address, card number, etc.
    val tel: String // copy of tel
)

I use ModelMapper for such works in Java, but it can't be used because data classes are final (ModelMapper creates CGLib proxies to read mapping definitions). We can use ModelMapper when we make these classes/fields open, but we must implement features of "data" class manually. (cf. ModelMapper examples: https://github.com/jhalterman/modelmapper/blob/master/examples/src/main/java/org/modelmapper/gettingstarted/GettingStartedExample.java)

How to map such "data" objects in Kotlin?

Update: ModelMapper automatically maps fields that have same name (like tel -> tel) without mapping declarations. I want to do it with data class of Kotlin.

Update: The purpose of each classes depends on what kind of application, but these are probably placed in the different layer of an application.

For example:

These classes are similar, but are not the same.

I want to avoid normal function calls for these reasons:

Of course, a library that has similar feature is intended, but information of the Kotlin feature is also welcome (like spreading in ECMAScript).

Upvotes: 112

Views: 144368

Answers (14)

labai
labai

Reputation: 81

LaMapper - is mapper for Kotlin, supports both - constructor parameters and properties mapping.

It uses bytecode generation at runtime, so performance is the same as handwritten code. No compiler plugins are required.

Example

fun PersonForm.toPersonRecord(): PersonRecord = LaMapper.copyFrom(this) {
    PersonRecord::code from PersonForm::personCode // property mapping
    PersonRecord::name from { "${it.firstName} ${it.lastName}" } // lambda mapping
    // all other properties are mapped by name
}

val rec = person.toPersonRecord()

In addition it has various data-type conversions by default (numbers, dates, enums etc.).

And, as it uses property references instead of strings for fields, it is more safe for refactoring.

Disclaimer: I'm the author.

Upvotes: 3

Ahmed Hosny
Ahmed Hosny

Reputation: 1

This is the best way ever to use ModelMapper in Kotlin, no need for Converters or TypeMappers. just use .apply{} extension function on the converted object:

modelmapper.map(myDTO, myEntity::clas.java).apply{
    myDTO.bar = foo(myEntity.bar)
}

below applys to the problem:

data class PersonRecord(
    var name: String? = null,
    var age: Int? = null,
    var tel: String? = null,
) {
    companion object {
        fun fromForm(personForm: PersonForm): PersonRecord = ModelMapper().map(personForm, PersonRecord::class.java)
            .apply {
                name = "${personForm.firstName} ${personForm.lastName}"
            }
    }
}

Upvotes: 0

Pratik Fagadiya
Pratik Fagadiya

Reputation: 1472

You can use kotlin extension function for transfer/convert one object to another object

Example:

data class PersonForm(
    val firstName: String? = null, 
    val lastName: String? = null, 
    val age: Int? = null,
    // maybe many fields exist here like address, card number, etc.
    val tel: String? = null
)

// maps to ...
data class PersonRecord(
    val name: String? = null, 
    val age: Int? = null, 
    val tel: String
)

Now create kotlin extension function for Convert / transfer into PersonRecord

fun PersonForm.transform(): PersonRecord {
    val name: String = this.firstName + " " + this.lastName
    val age: Int? = this.age
    val tel: String = this.tel.toString()
    return PersonRecord(name, age, tel)
}

and now you will be able to use it

fun getInfo() {
    val personrecord = PersonForm().transform()
    val finalName = personrecord.name  // This will be first name and last name
}

Upvotes: 1

王子1986
王子1986

Reputation: 3609

Try this kotlin library, it support both kotlin and java

https://github.com/krud-dev/shapeshift

Upvotes: 1

s0nicYouth
s0nicYouth

Reputation: 520

kMapper-object to object mapper specifically created for Kotlin. Uses compile time code generation, so no reflection. Interface description for a mapper looks like that:

@Mapper
internal interface BindMapper {
    fun map(dto: BindDto, @Bind second: Int, @Bind third: SomeInternalDto, @Bind(to = "fourth") pr: Double): BindDomain
}

More examples here.

Disclaimer: I'm the author.

Upvotes: 1

Jos
Jos

Reputation: 111

You can use the DataClassMapper class taken from here: https://github.com/jangalinski/kotlin-dataclass-mapper

data class PersonForm(
    val firstName: String,
    val lastName: String,
    val age: Int,
    // maybe many fields exist here like address, card number, etc.
    val tel: String
)

// maps to ...
data class PersonRecord(
    val name: String, // "${firstName} ${lastName}"
    val age: Int, // copy of age
    // maybe many fields exist here like address, card number, etc.
    val tel: String // copy of tel
)

fun mapPerson(person: PersonForm): PersonRecord =
    DataClassMapper<PersonForm, PersonRecord>()
        .targetParameterSupplier(PersonRecord::name) { "${it.firstName} ${it.lastName}"}
        .invoke(person)

fun main() {
    val result = mapPerson(PersonForm("first", "last", 25, "tel"))
    println(result)
}

Result will be:

PersonRecord(name=first last, age=25, tel=tel)

Upvotes: 0

Евгений Иванов
Евгений Иванов

Reputation: 291

MapStruct lets kapt generate classes doing the mapping (without reflection).

Use MapStruct:

@Mapper
interface PersonConverter {

    @Mapping(source = "phoneNumber", target = "phone")
    fun convertToDto(person: Person) : PersonDto

    @InheritInverseConfiguration
    fun convertToModel(personDto: PersonDto) : Person

}


// Note this either needs empty constructor or we need @KotlinBuilder as dsecribe below
data class Person: this(null, null, null, null) (...)

Use: 

val converter = Mappers.getMapper(PersonConverter::class.java) // or PersonConverterImpl()

val person = Person("Samuel", "Jackson", "0123 334466", LocalDate.of(1948, 12, 21))

val personDto = converter.convertToDto(person)
println(personDto)

val personModel = converter.convertToModel(personDto)
println(personModel)

Edit:

Now with @KotlinBuilder for avoiding constructor() issue:

GitHub: Pozo's mapstruct-kotlin

Annotate data classes with @KotlinBuilder. This will create a PersonBuilder class, which MapStruct uses, thus we avoid ruining the interface of the data class with a constructor().

@KotlinBuilder
data class Person(
    val firstName: String,
    val lastName: String,
    val age: Int,
    val tel: String
)

Dependency :

// https://mvnrepository.com/artifact/com.github.pozo/mapstruct-kotlin
api("com.github.pozo:mapstruct-kotlin:1.3.1.1")
kapt("com.github.pozo:mapstruct-kotlin-processor:1.3.1.1")

https://github.com/mapstruct/mapstruct-examples/tree/master/mapstruct-kotlin

Upvotes: 23

zack evein
zack evein

Reputation: 289

Using ModelMapper

/** Util.kt **/

class MapperDto() : ModelMapper() {
    init {
        configuration.matchingStrategy = MatchingStrategies.LOOSE
        configuration.fieldAccessLevel = Configuration.AccessLevel.PRIVATE
        configuration.isFieldMatchingEnabled = true
        configuration.isSkipNullEnabled = true
    }
}

object Mapper {
    val mapper = MapperDto()

    inline fun <S, reified T> convert(source: S): T = mapper.map(source, T::class.java)
}

Usage

val form = PersonForm(/** ... **/)
val record: PersonRecord = Mapper.convert(form)

You might need some mapping rules if the field names differ. See the getting started
PS: Use kotlin no-args plugin for having default no-arg constructor with your data classes

Upvotes: 8

Mike Placentra
Mike Placentra

Reputation: 885

For ModelMapper you could use Kotlin's no-arg compiler plugin, with which you can create an annotation that marks your data class to get a synthetic no-arg constructor for libraries that use reflection. Your data class needs to use var instead of val.

package com.example

annotation class NoArg

@NoArg
data class MyData(var myDatum: String)

mm.map(. . ., MyData::class.java)

and in build.gradle (see docs for Maven):

buildscript {
  . . .
  dependencies {
    classpath "org.jetbrains.kotlin:kotlin-gradle-plugin:$kotlinVersion"
  }
}

apply plugin: 'kotlin-noarg'

noArg {
  annotation "com.example.NoArg"
}

Upvotes: 3

Ken
Ken

Reputation: 791

You can use ModelMapper to map to a Kotlin data class. The keys are:

  • Use @JvmOverloads (generates a constructor with no arguments)
  • Default values for data class member

  • Mutable member, var instead of val

    data class AppSyncEvent @JvmOverloads constructor(
    var field: String = "",
    var arguments: Map<String, *> = mapOf<String, Any>(),
    var source: Map<String, *> = mapOf<String, Any>()
)

val event = ModelMapper().map(request, AppSyncEvent::class.java)

Upvotes: 2

Tom Power
Tom Power

Reputation: 1382

This works using Gson:

inline fun <reified T : Any> Any.mapTo(): T =
    GsonBuilder().create().run {
        toJson(this@mapTo).let { fromJson(it, T::class.java) }
    }

fun PersonForm.toRecord(): PersonRecord =
    mapTo<PersonRecord>().copy(
        name = "$firstName $lastName"
    )

fun PersonRecord.toForm(): PersonForm =
    mapTo<PersonForm>().copy(
        firstName = name.split(" ").first(),
        lastName = name.split(" ").last()
    )

with not nullable values allowed to be null because Gson uses sun.misc.Unsafe..

Upvotes: 4

klimat
klimat

Reputation: 25011

Is this are you looking for?

data class PersonRecord(val name: String, val age: Int, val tel: String){       
    object ModelMapper {
        fun from(form: PersonForm) = 
            PersonRecord(form.firstName + form.lastName, form.age, form.tel)           
    }
}

and then:

val personRecord = PersonRecord.ModelMapper.from(personForm)

Upvotes: 27

mfulton26
mfulton26

Reputation: 31274

  1. Simplest (best?):

    fun PersonForm.toPersonRecord() = PersonRecord(
        name = "$firstName $lastName",
        age = age,
        tel = tel
)

  2. Reflection (not great performance):

    fun PersonForm.toPersonRecord() = with(PersonRecord::class.primaryConstructor!!) {
    val propertiesByName = PersonForm::class.memberProperties.associateBy { it.name }
    callBy(args = parameters.associate { parameter ->
        parameter to when (parameter.name) {
            "name" -> "$firstName $lastName"
            else -> propertiesByName[parameter.name]?.get(this@toPersonRecord)
        }
    })
}

  3. Cached reflection (okay performance but not as fast as #1):

    open class Transformer<in T : Any, out R : Any>
protected constructor(inClass: KClass<T>, outClass: KClass<R>) {
    private val outConstructor = outClass.primaryConstructor!!
    private val inPropertiesByName by lazy {
        inClass.memberProperties.associateBy { it.name }
    }

    fun transform(data: T): R = with(outConstructor) {
        callBy(parameters.associate { parameter ->
            parameter to argFor(parameter, data)
        })
    }

    open fun argFor(parameter: KParameter, data: T): Any? {
        return inPropertiesByName[parameter.name]?.get(data)
    }
}

val personFormToPersonRecordTransformer = object
: Transformer<PersonForm, PersonRecord>(PersonForm::class, PersonRecord::class) {
    override fun argFor(parameter: KParameter, data: PersonForm): Any? {
        return when (parameter.name) {
            "name" -> with(data) { "$firstName $lastName" }
            else -> super.argFor(parameter, data)
        }
    }
}

fun PersonForm.toPersonRecord() = personFormToPersonRecordTransformer.transform(this)

  4. Storing Properties in a Map

    data class PersonForm(val map: Map<String, Any?>) {
    val firstName: String   by map
    val lastName: String    by map
    val age: Int            by map
    // maybe many fields exist here like address, card number, etc.
    val tel: String         by map
}

// maps to ...
data class PersonRecord(val map: Map<String, Any?>) {
    val name: String    by map // "${firstName} ${lastName}"
    val age: Int        by map // copy of age
    // maybe many fields exist here like address, card number, etc.
    val tel: String     by map // copy of tel
}

fun PersonForm.toPersonRecord() = PersonRecord(HashMap(map).apply {
    this["name"] = "${remove("firstName")} ${remove("lastName")}"
})

Upvotes: 96

voddan
voddan

Reputation: 33839

Do you really want a separate class for that? You can add properties to the original data class:

data class PersonForm(
    val firstName: String,
    val lastName: String,
    val age: Int,
    val tel: String
) {
    val name = "${firstName} ${lastName}"
}

Upvotes: 4

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