Reputation: 513
I want to do something like this.
Let's say we have a tensor A.
A = [[1,0],[0,4]]
And I want to get nonzero values and their indices from it.
Nonzero values: [1,4]
Nonzero indices: [[0,0],[1,1]]
There are similar operations in Numpy.
np.flatnonzero(A)
return indices that are non-zero in the flattened A.
x.ravel()[np.flatnonzero(x)]
extract elements according to non-zero indices.
Here's a link for these operations.
How can I do somthing like above Numpy operations in Tensorflow with python?
(Whether a matrix is flattened or not doesn't really matter.)
Upvotes: 35
Views: 39322
Reputation: 31
What about using sparse tensors.
>>> A = [[1,0],[0,4]]
>>> sparse = tf.sparse.from_dense(A)
>>> sparse.values.numpy(), sparse.indices.numpy()
(array([1, 4], dtype=int32), array([[0, 0],
[1, 1]]))
Upvotes: 0
Reputation: 579
#assume that an array has 0, 3.069711, 3.167817.
mask = tf.greater(array, 0)
non_zero_array = tf.boolean_mask(array, mask)
Upvotes: 6
Reputation: 4159
You can achieve same result in Tensorflow using not_equal and where methods.
zero = tf.constant(0, dtype=tf.float32)
where = tf.not_equal(A, zero)
where
is a tensor of the same shape as A
holding True
or False
, in the following case
[[True, False],
[False, True]]
This would be sufficient to select zero or non-zero elements from A
. If you want to obtain indices you can use where
method as follows:
indices = tf.where(where)
where
tensor has two True
values so indices
tensor will have two entries. where
tensor has rank of two, so entries will have two indices:
[[0, 0],
[1, 1]]
Upvotes: 50