Reputation: 209
I need to send this HTML block as a response(or request?) to ajax script, probably I also need this php part... Basically i want to open a modal box with data generated from variable that i am getting from JS, and when a tried to generate my modal outside of ajax it didnt update well.
if(!empty($_SESSION['modalBoxID'])){
$sql = "SELECT * FROM vehicle WHERE vehicle.id='{$_SESSION['modalBoxID']}'";
$sqlquery = $db->query($sql);
$_SESSION['modalBoxID'] = NULL;
}
?>
<div class="modal-body display-content">
<div class="container-fluid">
<?php while($details = mysqli_fetch_assoc($sqlquery)) : ?>
<div class="col-md-4"><img src=<?php echo $details['image'];?> class="image-responsive">
<div class="col-sm-6">
<form action="add_cart.php" method="post">
<div class="form-group">
<label for="quantity">Quantity:</label>
<input type="text" class="form-control" id="quantity" name="quantity">
</div>
</form>
</div>
<div class="col-sm-6">
<br/>
<button type="button" class="add-to-basket btn btn-success" >ADD TO CART</button>
</div>
</div>
<div class="col-md-1"></div>
<div class="col-md-7" id="desc">
<p><b>Model:</b> <?php echo $details['model'];?></p>
<p><b>Engine:</b> <?php echo $details['engine'];?></p>
<h4>Description</h4>
<p><?php echo $details['description'];?></p>
<hr>
<hr>
</div>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
<?php endwhile; ?>
</div>
Here is JS script that i need to send it to
$(document).ready(function(){
// Otevre modal
$('.show-modal').click(function(){
var product_id = $(this).attr('data-id');
$.ajax({
type: 'POST',
cache: false,
data: {modalID : product_id},
url: 'includes/getID.php', // tomuto souboru predas idecko produktu, zapises do kosiku atd.
success: function(data) {
$('.modal-body').html(data)
$("#itemBox").modal('show');
// treba nejaka hlaska, ze byl pridan do kosiku
}
});
// kod co otevre modal, mkrni na bootstrap manual jak je otevira nebo si otevreni nadefinuj sa
//$('.product_id').val(productID);
});
$(document.body).on('hidden.bs.modal', function () {
$("#itemBox").removeData('bs.modal');
});
Upvotes: 1
Views: 4323
Reputation: 209
I solved the problem by modifing my JS to look like this
$(document).ready(function(){
// Otevre modal
$('.show-modal').click(function(){
var product_id = $(this).attr('data-id');
$.ajax({
type: 'POST',
cache: false,
data: {modalID : product_id},
//datatype: 'html',
url: 'includes/getID.php', // tomuto souboru predas idecko produktu, zapises do kosiku atd.
success: function(data) {
$("#itemBox").attr('data-id',product_id)
$("#itemBox").modal('show').on('shown.bs.modal', function () {
$(this).find(".modal-content").html(data)
});
// treba nejaka hlaska, ze byl pridan do kosiku
}
});
});
Upvotes: 0
Reputation: 21892
You're missing a couple quotes in the php...
....and you'll want to use dataType: 'html'
for the ajax call.
$('.show-modal').click(function(){
var product_id = $(this).attr('data-id');
$.ajax({
type: 'POST',
cache: false,
data: ({modalID : product_id}),
dataType: 'html',
url: 'includes/getID.php', // tomuto souboru predas idecko produktu, zapises do kosiku atd.
success: function(data) {
$('.modal-body').html(data)
$("#itemBox").modal('show');
// treba nejaka hlaska, ze byl pridan do kosiku
}
});
Upvotes: 1