Reputation: 4517
I have a Text
object that contains some number of Latin characters that needs to be converted to a unicode escape sequence of the format \u####
with #
being hex digits
As described here, haskell easily converts strings to escape sequences and vice versa. However, it will only go to the decimal representation. For example,
> let s = "Ñ"
> s
"\209"
Is there a way to specify the escape sequence encoding to force it to spit out in the correct format? i.e
> let s = encodeUnicode16 "Ñ"
> s
"\u00d1"
Upvotes: 3
Views: 1082
Reputation: 23850
How about this:
import Text.Printf (printf)
encodeUnicode16 :: String -> String
encodeUnicode16 = concatMap escapeChar
where
escapeChar c
| ' ' <= c && c <= 'z' = [c]
| otherwise =
printf "\\u%04x" (fromEnum c)
I ghci, you can use it as follows:
> putStrLn $ encodeUnicode16 "Ñ"
\u00d1
Note that if you don't use putStrLn
it will get escaped twice:
> encodeUnicode16 "Ñ"
"\\u00d1"
This is because ghci will implicitly add a print
in front of the command.
Edit: I missed that part that you have a Text
and not a String
. Here's the same code for Text
:
import Data.Text (Text)
import qualified Data.Text as T
import qualified Data.Text.IO as T
import Text.Printf (printf)
encodeUnicode16 :: Text -> Text
encodeUnicode16 = T.concatMap escapeChar
where
escapeChar c
| ' ' <= c && c <= 'z' = T.singleton c
| otherwise =
T.pack $ printf "\\u%04x" (fromEnum c)
Again, you want to use T.putStrLn
to avoid double escaping everything.
Upvotes: 4