CODEWITHSUNDEEP
javahtmlseleniumxpathselenium-webdriver
jenish patel
jenish patel

Reputation: 1

how to locate element using xpath

<a ui-sref="apps.service" href="#/apps/service">
  <i class="glyphicon glyphicon-list icon zoom-icon text-info-dker"></i>
  <span class="font-bold"> Service</span>
</a>

How can I locate the element?

driver.findElement(By.partialLinkText("service")).click();
driver.findElement(By.xpath("ui[href$=services]"));

Upvotes: 0

Views: 192

Answers (4)

kjhughes
kjhughes

Reputation: 111786

This XPath,

//a[normalize-space() = 'Service']

will select all a elements whose normalized string value equals "Service" -- perfect for the example you show.

Be wary of solutions based upon contains() as they will also match strings that include additional leading or trailing text, which may or may not be what you want.

Upvotes: 0

Eby
Eby

Reputation: 396

It is better to use contains in to locate element in this xpath. The below xpath will be accurate.

driver.findElement(By.xpath("//a/span[contains(text(),'Service')]")

Upvotes: 0

Saurabh Gaur
Saurabh Gaur

Reputation: 23845

You should try using xpath with WebDriverWait to wait until element visible and enable as below :-

new WebDriverWait(driver, 10).until(ExpectedConditions.elementToBeClickable(By.xpath(".//a[contains(.,'Service')]"))).click();

Upvotes: 0

Guy
Guy

Reputation: 51009

partialLinkText is case sensitive. Try

driver.findElement(By.partialLinkText("Service")).click();

The element is in <a> tag, not <ui> tag

driver.findElement(By.xpath(".//a[href*='services']"));

Upvotes: 1

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