CODEWITHSUNDEEP
c++filepath
Boat
Boat

Reputation: 529

Filepath with variable inside c++

I am trying to use a variable in my file path.

I have succeeded in adding one for the name of the files, but not for the folder name.

string utilisateur, mot_de_passe;
int gr;

cout << " Entrer un nom utilisateur:"; cin >> utilisateur;
cout << " Entrer un mot de passe :"; cin >> mot_de_passe;
cout << "Choisir un groupe:"; cin >> gr;

ofstream dossier;
if (gr == 1)
{
    dossier.open("C:/Users/titib/Contacts/Desktop/Projet informatique/groupe/" + utilisateur + ".txt");
    dossier << utilisateur << endl << mot_de_passe << endl << gr << endl;

I would like to use the variable gr as the name of the folder.

dossier.open("C:/Users/titib/Contacts/Desktop/Projet informatique/groupe/**gr**" + utilisateur + ".txt");

Upvotes: 4

Views: 3579

Answers (3)

Boat
Boat

Reputation: 529

Okay i finnaly succeed to create a file. Thanks to Remy Lebeau.

Actually i changed few things :

  • gr is name groupe now -groupe is a string to avoid conversion

i used filedirectory . Here the code 

std::ostringstream gr;

        gr << "C:/Users/titib/Contacts/Desktop/Projet informatique/" << groupe;

        CreateDirectory(gr.str().c_str(), NULL);

        dossier.open("C:/Users/titib/Contacts/Desktop/Projet informatique/" + groupe + "/" + utilisateur + ".txt");
        dossier << utilisateur << endl << mot_de_passe << endl << groupe << endl;

Thanks again.

Upvotes: 0

Remy Lebeau
Remy Lebeau

Reputation: 596352

You need to convert gr to a std::string before you can append it to another string. Prior to C++11, you can use std::ostringstream for that, eg:

#include <sstream>

std::ostringstream oss_gr;
oss_gr << gr;

dossier.open("C:/Users/titib/Contacts/Desktop/Projet informatique/groupe/" + oss_gr.str() + "/" + utilisateur + ".txt");

Or, if you are using C++11 or later, you can use std::to_string() instead:

dossier.open("C:/Users/titib/Contacts/Desktop/Projet informatique/groupe/" + std::to_string(gr) + "/" + utilisateur + ".txt");

Alternatively, in any C++ version, you could use std::ostringstring to format the entire path instead:

std::ostringstream oss_path;
oss_path << "C:/Users/titib/Contacts/Desktop/Projet informatique/groupe/" << gr << "/" << utilisateur << ".txt";
dossier.open(oss_path.str());

Upvotes: 1

Khalil Khalaf
Khalil Khalaf

Reputation: 9407

This should work just fine:

std::string FilePath = "C:/Users/titib/Contacts/Desktop/Projet informatique/groupe/" + std::to_string(gr)  + "/" + utilisateur + ".txt";
dossier.open(FilePath);

Upvotes: 2

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