CODEWITHSUNDEEP
ruby
Richlewis
Richlewis

Reputation: 15384

Split URL based on characters in Ruby

I was wondering how best to go about splitting the following string by / but ignoring certain characters

So my string will look like this

url = http://10.0.3.2/i/av/Genymotionvbox86p/android/10~3~1/0/-/-/a3306aa6~0346~4ad5~bdf5~1bc7c20a88ab/0/test~page/-/-/video/live/-/one_hd/-/0/1/0~0/-/0~0/0~0/?trace=skwthffdsy

I want to split by / ignoring the http:// and the query string at the end, the desired outcome would look like

["i", "av", "Genymotionvbox86p", "android", "10~3~1", "0", "-", "-",
  "a3306aa6~0346~4ad5~bdf5~1bc7c20a88ab", "0", "test~page", "-", "-",
  "video", "live", "-", "one_hd", "-", "0", "1", "0~0", "-", "0~0", "0~0"]

So at the moment url.split('/') gets me so far but its the excluding or certain characters I am stuck on

Maybe using scan would serve me better?

Upvotes: 1

Views: 453

Answers (2)

kxmh42
kxmh42

Reputation: 3830

Try this:

require 'uri'
URI(url).path.sub(%r{^/}, "").split("/")

Edit: why use gsub when shorter and faster sub is perfectly fine.

Upvotes: 5

Bartłomiej Gładys
Bartłomiej Gładys

Reputation: 4615

maybe something like this? 

url.split('/')[3..-2]

[3..-2] means scope of array, it takes all elements from index 3 to index -2

-2

means one before last

Upvotes: 1

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