Reputation: 546
In rxjs5 doc, it mentions 'To reduce polymorphism and get better performance out of operators, some operators have been split into more than one operator'. What does it actually mean and how to use the mergeMapTo operator?
Upvotes: 4
Views: 5466
Reputation: 6240
From the docs, mergeMapTo:
It's like
mergeMap
, but maps each value always to the same inner Observable.
I see mergeMapTo
as a shortcut to always output the same value. mergeMapTo
doesn't care about the source value.
Also from the docs:
Maps each source value to the given Observable innerObservable regardless of the source value, and then merges those resulting Observables into one single Observable, which is the output Observable.
You'll see that mergeMap
takes a function
while mergeMapTo
takes a value
:
An example with mergeMap
(we're transforming values):
Rx.Observable.of(1, 2, 3).mergeMap(x =>
Rx.Observable.interval(1000).map(i => x+i)
);
While using mergeMapTo we can take values from a stream and always output the same value (also transforming, but always to the same value):
Rx.Observable.of(1, 2, 3).mergeMapTo(10);
Upvotes: 6