Reputation: 123
I'm currently submitting data via a POST request using the below jquery ajax method and I'm successfully getting a return result in my console (see below) that displays the JSON request that was submitted to the server. However I CANNOT figure out how to parse the JSON object in my Django view. What do I write my view so I can Parse my JSON object and get a hold of "schedule_name" to execute the below command in my Django view. Please see a copy of my view below.
Schedule.objects.create(schedule_name = Schedule)
$.ajax({
type: "POST",
url: "{% url 'addSchedule' building_pk %}",
dataType: "json",
data: {"json_items" : JSON.stringify(Schedule_Info)},
success : function(data)
{
$('.todo-item').val(''); // remove the value from the input
console.log(data); // log the returned json to the console
console.log("success"); // another sanity check
alert("Sucess");
},
JSON output in console after submitting request
json-items: "{
"nameOfSchedule":{"schedule_name":"Schedule"},
"Rooms":[
{"room_rank":"1","room_name":"Room 101 "},
{"room_rank":"2","room_name":"Room 102 "},
{"room_rank":"3","room_name":"Room 103 "},
{"room_rank":"4","room_name":"Room 104 "}
],
"Users":[
{"user_name":"[email protected]"},
{"user_name":"[email protected]"}
]
}"
Django View
def addSchedule(request, building_id):
building_pk = building_id
b = Building.objects.get(pk=building_pk)
floor_query = b.floor_set.all()
master_query = floor_query.prefetch_related('room_set').all()
if request.is_ajax() and request.POST:
data = request.POST
### Input the schedule name in the datase by parsing the JSON object
return HttpResponse(json.dumps(data),content_type="application/json")
else:
return render(request, 'scheduler/addSchedule.html', {'building_pk' : building_pk,
'building_query': master_query
})
Upvotes: 0
Views: 3275
Reputation: 123
I resolved the issue by making the following changes to my Django
Django view
data = json.loads(request.POST.get('json_items'))
name = data['nameOfSchedule']['schedule_name']
Schedule.objects.create(schedule_name = name)
Upvotes: 3
Reputation: 916
You could use the JsonResponse for that:
return JsonResponse({'this': "will be converted to json"});
See https://docs.djangoproject.com/el/1.10/ref/request-response/ for more info
Upvotes: 0