CODEWITHSUNDEEP
phphtmlmysql
dukeispie
dukeispie

Reputation: 83

Getting number from database, then subtracting it doesn't work

I have tried creating a script to prevent spamming. Every 30 seconds will allow you to post again. I am using time() to use it (php unix time) and then uploading it to the user's profile. So lastpost=time(); (basically)

$ayy = $user['lastpost'];
die($ayy);

That returns the user last posted. For this example, the last time the user has posted was 14423658. When I apply simple math to it, such as

die($ayy - 3);

it will output nothing. If I convert the value to a integer, doing

$ayy = intval($user['lastpost']);

The $ayy value will just become null (blank). How I know this is when I perform

die($ayy);

It outputs nothing. If I do

$ayy = intval($user['lastpost']);
die($ayy - 1);

or

$ayy = $user['lastpost'];
die(intval($ayy - 1));

They all output nothing. You'd expect something like this to be very simple, but I have spent days pondering this, and it is really frustrating.

If you do contribute, thanks.

EDIT When var_dump is applied to $ayy, this is what it outputs: string(14423658) when intval is applied to $ayy, this is also what it outputs: int(14423658). It was working the whole time (with intval) but it didn't output anything. Problem Solved, but why is it outputting blank?

Upvotes: 0

Views: 32

Answers (1)

Andrej
Andrej

Reputation: 7504

According to manual http://php.net/manual/en/function.exit.php (exit is equivalent for die):

if status is integer it's not printed.

If you want to print it with die(I don't know why) do like this die((string)$ayy).

Upvotes: 2

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