CODEWITHSUNDEEP
phpajax
Josip Gòdly Zirdum
Josip Gòdly Zirdum

Reputation: 717

How to call a php function from ajax?

I am familiar of how to get ajax to go to a php page an execute a series of things and then return json data. However is it possible to call a specific function which resides in a given page?

Basically what I want is to reduce the number of files in a project. So I can put a lot of common functions in one page and then just call whatever the function that I want at the moment.

Upvotes: 27

Views: 176992

Answers (5)

Asef Hossini
Asef Hossini

Reputation: 755

As a structure for this kind of purposes, I suggest this:

PHP

<?php
    if(isset($_POST['action'])){
        if ($_POST['action'] == "function1") { func1(); }
        if ($_POST['action'] == "function2") { func2(); }
        if ($_POST['action'] == "function3") { func3(); }
        if ($_POST['action'] == "function4") { func4(); }
    }

    function func1(){
        //Do something here
        echo 'test';
    }
?>

jQuery

var data = { action: 'function1' };

$.post(ajaxUrl, data, function(response) {
    if(response != "") {
        $('#SomeElement').html(response);
    }else{
        alert('Error, Please try again.');
    }
});

As mentioned, you can't call a PHP function directly from an AJAX call.

Upvotes: 8

Vishnu Bhadoriya
Vishnu Bhadoriya

Reputation: 1676

You cannot call a PHP function directly from an AJAX request, but you can do this instead:

<? php 
    function test($data){
        return $data+1;
    }

    if (isset($_POST['callFunc1'])) {
        echo test($_POST['callFunc1']);
    }
?>
<script>
    $.ajax({
        url: 'myFunctions.php',
        type: 'post',
        data: { "callFunc1": "1"},
        success: function(response) { console.log(response); }
    });
</script>

Upvotes: 23

Rajendra Rajput
Rajendra Rajput

Reputation: 85

jquery:

$(document).ready(function(){
    $('#tfa_1117700').change(function(){
        var inputValue = $(this).val();
        var v_token = "{{csrf_token()}}";
        $.post(
            "{{url('/each-child')}}",
            { dropdownValue: inputValue,_token:v_token },
            function(data){
                console.log(data);
                $('#each-child-html').html(data);
            }
        );
    });
});

php:

public function EachChild(Request $request)
{
    $html ="";
    for ($i=1; $i <= $request->dropdownValue; $i++)
    { 
        $html = $i;
    }
    echo $html;
}

Upvotes: 0

Nitheesh K P
Nitheesh K P

Reputation: 1110

For AJAX request

  1. Include jQuery Library in your web page. For e.g.

    <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>

  2. Call a function on button click

    <button type="button" onclick="create()">Click Me</button>

  3. While click on button, call create function in JavaScript.

    <script>
    function create () {
        $.ajax({
            url:"test.php",    //the page containing php script
            type: "post",    //request type,
            dataType: 'json',
            data: {registration: "success", name: "xyz", email: "[email protected]"},
            success:function(result){
                console.log(result.abc);
            }
        });
    }
</script>

On the server side test.php file, the action POST parameter should be read and the corresponding value and do the action in PHP and return in JSON format e.g.

$registration = $_POST['registration'];
$name= $_POST['name'];
$email= $_POST['email'];

if ($registration == "success"){
    // some action goes here under php
    echo json_encode(array("abc"=>'successfuly registered'));
}

Upvotes: 32

iliaz
iliaz

Reputation: 395

If I understand correctly, yes you can. Put all your functions in one php file and have the ajax pass as a parameter which one you want to call. Then with a switch or if structure, execute the one you want.

Upvotes: 3

Related Questions