CODEWITHSUNDEEP
javaandroidxmlparsing
vivek_Android
vivek_Android

Reputation: 1697

Access Soap based Web Service in Android

I'm calling an webservice which is soap based in my Android application. It is returning me the XML response. How can I parse it? I checked the XML parsing its asking for the URL. I'm confused about which URL I need to pass?

Here is the code:

SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);  request.addProperty("pStrType", type);

request.addProperty("pIntPageNo", PageNo) 

request.addProperty("pIntPageSize", PageSize);

           //Log.v(LOG_TAG," value:="+name);

           //Log.v(LOG_TAG," value:="+pass);
           SoapSerializationEnvelope envelope = 
           new SoapSerializationEnvelope(SoapEnvelope.VER11);
           envelope.dotNet = true;
           envelope.setOutputSoapObject(request);
           AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(URL);
           try
           {
           androidHttpTransport.call(SOAP_ACTION, envelope);
           SoapObject resultstring = (SoapObject) envelope.bodyIn; 
           Log.v(LOG_TAG," value:="+resultstring);
           String Result=resultstring.toString();

What to do after this? I'm getting the string of response in (resultString).

Upvotes: 1

Views: 415

Answers (3)

Ibraheem Osama
Ibraheem Osama

Reputation: 334

Try to use HttpTransportSE instead of HttpTransport and use object instead of soapObject try this code 

  HttpTransportSE http = new HttpTransportSE("http://10.0.2.2:2612/Service1.svc");

  http.call("http://tempuri.org/IService1/GetCoursesInfos", envelope);

  Object result= (Object)envelope.getResponse();
  message=result.toString();

Check this code and tell me This post tells you how to consume soap web service

Upvotes: 0

Akash Kava
Akash Kava

Reputation: 39916

Disclaimer: I am going to suggest product of my own company, but its a good suggestion for this question.

You need to get some sort of Code generator like WSClient++

Upvotes: 0

Ramp
Ramp

Reputation: 1782

If you know how to use SAX XML Parser, you can convert the String into a byte stream and pass it to your handler.

    String result=resultstring.toString();
    SAXParser saxP = SAXParserFactory.newInstance().newSAXParser();
    ResponseHandler respH = new ResponseHandler();//your implementation
    saxP.parse(new ByteArrayInputStream(result.getBytes()), respH);

If you don't know SAX parser, i would advice you to learn that first. It is simple.

Hope that helps.

Upvotes: 2

Related Questions