Reputation: 2093
I tried this:
pd.date_range(2000, periods = 365, freq = 'D',format = '%d-%m-%Y')
why I am getting this result:
DatetimeIndex(['1970-01-01 00:00:00.000002', '1970-01-02 00:00:00.000002',
'1970-01-03 00:00:00.000002', '1970-01-04 00:00:00.000002',
'1970-01-05 00:00:00.000002', '1970-01-06 00:00:00.000002',
'1970-01-07 00:00:00.000002', '1970-01-08 00:00:00.000002',
Any help?
Upvotes: 2
Views: 287
Reputation: 862406
You need add ''
to 2000
only:
print (pd.date_range('2000', periods = 365, freq = 'D'))
DatetimeIndex(['2000-01-01', '2000-01-02', '2000-01-03', '2000-01-04',
'2000-01-05', '2000-01-06', '2000-01-07', '2000-01-08',
'2000-01-09', '2000-01-10',
...
'2000-12-21', '2000-12-22', '2000-12-23', '2000-12-24',
'2000-12-25', '2000-12-26', '2000-12-27', '2000-12-28',
'2000-12-29', '2000-12-30'],
dtype='datetime64[ns]', length=365, freq='D')
If use int
, cast it to str
:
print (pd.date_range(str(2000), periods = 365, freq = 'D'))
Upvotes: 2
Reputation: 410
Try this
pd.date_range('1/1/2000', periods = 365, freq = 'D',format = '%d-%m-%Y')
Upvotes: 1