Reputation: 551
I'm trying to make a recursive call to handle_call/3 before replying.
But it seems to not be possible, because a timeout
exit exception is thrown.
Below you can see the code and the error.
The code:
-module(test).
-behavior(gen_server).
%% API
-export([start_link/0,init/1,handle_info/2,first_call/1,second_call/1, handle_call/3, terminate/2]).
-record(state, {whatever}).
start_link() ->
gen_server:start_link({local, ?MODULE}, ?MODULE, [], []).
init(_Args) ->
{ok, #state{}}.
handle_info(Data, State) ->
{noreply, State}.
% synchronous messages
handle_call(_Request, _From, State) ->
case _Request of
first_call ->
{reply, data1, State};
second_call ->
{reply, {data2, first_call(self())}, State}
end.
first_call(Pid) ->
gen_server:call(Pid, first_call).
second_call(Pid) ->
gen_server:call(Pid, second_call).
terminate(_Reason, _State) ->
ok.
The error:
2> {_, PID} = test:start_link().
{ok,<0.64.0>}
3> test:second_call(PID).
** exception exit: {timeout,{gen_server,call,[<0.64.0>,second_call]}}
in function gen_server:call/2 (gen_server.erl, line 204)
A possible reason for this behaviour is that gen_server is not able to handle recursive calls until the first one is done (creating a deadlock). Is this the right reason, and if yes why? Thanks.
Upvotes: 1
Views: 501
Reputation: 41648
Yes, that is the reason. The gen_server is a single process, and while handle_call
is executing it doesn't pick up any messages nor respond to any gen_server:call
. Therefore first_call(self())
times out.
Upvotes: 6