Python Regex Matching characters

Question

I am trying to learn Python regular expressions. I have a long string that contains many patterns that look like: #v=xxxxxxxxxx where x is the variable characters I want.

I was thinking I could use re.findall(r'...', myString) where ... is my pattern. That's the part I'm having trouble with. I somehow need to get the next 10 characters after each #v=.

All help is appreciated :)

Answer 1

You were close! Here's an RE that'll work:

In [1]: import re

In [2]: s = "#v=yyyyyyyyyy #v=xxxxxxxxxx #v=zzzzzzzzzz"

In [3]: re.findall(r'#v=(\w{10})', s)
Out[3]: ['yyyyyyyyyy', 'xxxxxxxxxx', 'zzzzzzzzzz']