Reputation: 65
Is there way to deserialize invalid json?
For example, next JSON deserialization will fail with JsonReaderException
{
'sessionId': 's0j1',
'commandId': 19,
'options': invalidValue // invalid value
}
because options
property value is invalid.
Is there a nice way to get sessionId
and commandId
values even if options
value is invalid?
I know it's possible to handle errors during deserialization (http://www.newtonsoft.com/json/help/html/SerializationErrorHandling.htm)
var json = "{'sessionId': 's0j1', 'commandId': 19, 'options': invalidValue}";
var settings = new JsonSerializerSettings
{
Error = delegate(object sender, ErrorEventArgs args)
{
args.ErrorContext.Handled = true;
}
});
var result = JsonConvert.DeserializeObject(json, settings);
Bit it will result in result = null
.
Upvotes: 4
Views: 8840
Reputation: 4261
You can do it with JsonReader
.
Example code:
var result = new Dictionary<string, object>();
using (var reader = new JsonTextReader(new StringReader(yourJsonString)))
{
var lastProp = string.Empty;
try
{
while (reader.Read())
{
if (reader.TokenType == JsonToken.PropertyName)
{
lastProp = reader.Value.ToString();
}
if (reader.TokenType == JsonToken.Integer ||
reader.TokenType == JsonToken.String)
{
result.Add(lastProp, reader.Value);
}
}
}
catch(JsonReaderException jre)
{
//do anything what you want with exception
}
}
Note, that there is try..catch
block as when JsonReader
meets invalid character it throws JsonReaderException
on reader.Read()
Upvotes: 4