CODEWITHSUNDEEP
javaregexjsoup
Guo Eason
Guo Eason

Reputation: 3

Java regex , jsoup

How to extract these messages by regex or jsoup ? 19040172b-1、 SQL Server Develop 、zheng 、3-5,7-14 、D-101 ， 

<div id="AE9D7F630640426F8457A661607D2B8E-5-2" style="display: none;" class="kbcontent">
  19040172b-1
  <br>SQL Server Develop
  <br>
  <font title="teacher">zheng</font>
  <br>
  <font title="week">3-5,7-14</font>
  <br>
  <font title="classroom">D-101</font>
  <br>
 </div>

I have tried the following ways but failed.

1. Pattern pattern = Pattern.compile(">(.*?)<br>");

2. Elements msg = doc.select(":matchesOwn([>.*?<br>])");

Upvotes: 0

Views: 204

Answers (2)

dakatamen
dakatamen

Reputation: 11

1) First, it's never a good idea to parse HTMl with a regex. You can read more about that here.

2)You can just take all text between tags.

Document doc = Jsoup.parse(file, charsetName);
String text= doc.text();
System.out.println(text);

Upvotes: 1

bilgec
bilgec

Reputation: 161

String html = "<div id=\"AE9D7F630640426F8457A661607D2B8E-5-2\" style=\"display: none;\" class=\"kbcontent\">  19040172b-1  <br>SQL Server Develop  <br>  <font title=\"teacher\">zheng</font>  <br>  <font title=\"week\">3-5,7-14</font>  <br>  <font title=\"classroom\">D-101</font>  <br> </div> ";
html = html.replaceAll("<br>", "#~#");
Document doc = Jsoup.parse(html.toString());
String newHtml = doc.text();
String[] ary = newHtml.split("#~#");

This will do the job, yet there may be other clean ways to replace the br tag.

Upvotes: 0

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