Reputation: 2675
I want to know what exactly an asterisk does before a variable name in Kotlin.
I saw this (*args
) in a Spring boot Kotlin example:
@SpringBootApplication
open class Application {
@Bean
open fun init(repository: CustomerRepository) = CommandLineRunner {
repository.save(Customer("Jack", "Bauer"))
repository.save(Customer("Chloe", "O'Brian"))
repository.save(Customer("Kim", "Bauer"))
repository.save(Customer("David", "Palmer"))
repository.save(Customer("Michelle", "Dessler"))
}
}
fun main(args: Array<String>) {
SpringApplication.run(Application::class.java, *args)
}
Upvotes: 174
Views: 73135
Reputation: 8305
Consider a function which accepts a vararg (Variable number of arguments) parameter like below:
fun sum (vararg data: Int) {
// function body here
}
We can call this method with
sum(1,2,3,4,5)
But if we have these same values in an array, like:
val array = intArrayOf(1,2,3,4,5)
Then, we can call this method using the spread operator, like:
sum(*array)
Here, *(spread operator) will pass all the content of the array to the function.
*array is equivalent to 1,2,3,4,5
But a call like this:
sum(array)
will give us Type Mismatch compile time error:
Type mismatch. Required:Int Found:IntArray
This is because the array sum(array)
will be passed as IntArray
, but this call sum(*array)
will pass the contents of the array to the function.
Upvotes: 9
Reputation: 6349
The *
operator is known as the Spread Operator in Kotlin.
From the Kotlin Reference:
When you call a
vararg
-function, you can pass arguments individually, for exampleasList(1, 2, 3)
. if you already have an array and want to pass its contents to the function, use the spread operator (prefix the array with*
):
It can be applied to an Array before passing it into a function that accepts vararg
.
If you have a function that accepts a varied number of arguments...
fun sumOfNumbers(vararg numbers: Int): Int {
return numbers.sum()
}
Use the spread operator to pass an array's elements as the arguments:
val numbers = intArrayOf(2, 3, 4)
val sum = sumOfNumbers(*numbers)
println(sum) // Prints '9'
Notes:
*
operator is also the multiplication operator (of course).vararg
-function. This is demonstrated in the example here.apply
function in various functional programming languages.Upvotes: 294
Reputation: 1355
In Java you can pass an array as is but an advantage of unpacking an array with spread operator *
is that spread operator lets you combine the values from an array and some fixed values in a single call. Java doesn't support this.
Upvotes: 7
Reputation: 85946
In addition to the answers that were directly towards "what is this thing!?!", you often have the case where you have a List
and want to pass it to a function that is expecting a vararg
. For this, the conversion is:
someFunc(x, y, *myList.toTypedArray())
Assuming that last parameter of someFunc
is vararg
of the same type as the elements in the list.
Upvotes: 35
Reputation: 41638
As described in the documentation this is a spread operator:
When we call a vararg-function, we can pass arguments one-by-one, e.g. asList(1, 2, 3), or, if we already have an array and want to pass its contents to the function, we use the spread operator (prefix the array with *):
val a = arrayOf(1, 2, 3) val list = asList(-1, 0, *a, 4)
Upvotes: 13